When potassium permanganate (KMnO4) reacts with formaldehyde (HCHO), it undergoes oxidation-reduction reaction. The purple color of KMnO4 fades as it gets reduced to Mn2+ ions, while formaldehyde is oxidized to formic acid (HCOOH) or carbon dioxide and water. Heat may be evolved during the reaction.
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
Bromine reacts with an alkane to produce a colorless solution, due to the formation of a colorless alkyl halide. On the other hand, potassium permanganate (KMnO4) reacts with an alkane to form a brown precipitate of manganese dioxide.
Benzene cannot decolorize KMnO4 because it does not undergo addition reactions due to its stable aromatic structure. Alkenes, on the other hand, can decolorize KMnO4 because they can undergo addition reactions with KMnO4, breaking the double bond and forming a colorless product.
The ratio of equivalent weight of KMnO4 in acidic to basic medium is 1:2:5. In acidic medium, KMnO4 reacts as MnO4^- + 8H+ + 5e^- → Mn^2+ + 4H2O, requiring 5 equivalents, whereas in basic medium, it reacts as MnO4^- + 2H2O + 3e^- → MnO2 + 4OH^-, requiring 2 equivalents. In neutral medium, the equivalent weight is the same as in basic medium.
The formula for potassium permanganate is KMnO4
The purple KMnO4 is decolourise
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
Bromine reacts with an alkane to produce a colorless solution, due to the formation of a colorless alkyl halide. On the other hand, potassium permanganate (KMnO4) reacts with an alkane to form a brown precipitate of manganese dioxide.
The evolved gas is carbon dioxide (CO2).
Benzene cannot decolorize KMnO4 because it does not undergo addition reactions due to its stable aromatic structure. Alkenes, on the other hand, can decolorize KMnO4 because they can undergo addition reactions with KMnO4, breaking the double bond and forming a colorless product.
The ratio of equivalent weight of KMnO4 in acidic to basic medium is 1:2:5. In acidic medium, KMnO4 reacts as MnO4^- + 8H+ + 5e^- → Mn^2+ + 4H2O, requiring 5 equivalents, whereas in basic medium, it reacts as MnO4^- + 2H2O + 3e^- → MnO2 + 4OH^-, requiring 2 equivalents. In neutral medium, the equivalent weight is the same as in basic medium.
The formula for potassium permanganate is KMnO4
Alkenes react with potassium permanganate (KMnO4) through a process called oxidative cleavage, where the double bond is broken and oxygen atoms are added to the carbon atoms. This reaction results in the formation of diols (glycols) or ketones and carboxylic acids, depending on the conditions and the structure of the alkene.
The compound HCHO is called formaldehyde. It is a colorless, pungent gas that is commonly used in the manufacturing of various materials, including furniture, textiles, and resins.
When ethanol is oxidized with acidified KMnO4 solution, it undergoes complete oxidation to form ethanoic acid (acetic acid). The purple KMnO4 solution is reduced to green Mn2+ ions in the process.
When toluene is treated with alkaline KMnO4, it undergoes oxidation. Toluene is converted to benzyl alcohol, and further oxidation can convert benzyl alcohol to benzoic acid. The purple color of the KMnO4 solution will fade as the reaction proceeds.
acidicness number of kmno4