To find out how many milligrams are in 27 grams, you would multiply 27 grams by 1000 milligrams/gram. This equals 27,000 milligrams.
This reaction is not at equilibrium yet since the reaction quotient, Q, is not equal to the equilibrium constant, K. In this case, Q = (0.03)^2 / ((0.01)*(0.02))^2 = 0.45, which is greater than K = 0.15. Therefore, the reaction will proceed in the reverse direction to reach equilibrium.
142g The conversion formula: 5 oz* 28.34952313 g 1 oz = 141.7476156 g
To find the value of G at 100 K, you can use the equation ΔG = ΔH - TΔS. Plugging in the values, you get ΔG = 27 kJ/mol - (100 K)(0.09 kJ/molK) = 18 kJ/mol. Therefore, the value for G at 100 K would be 18 kJ/mol.
The original sample had a mass of 0.985 g. After losing 0.135 g of H2O, the new mass of the sample is 0.985 g - 0.135 g = 0.85 g. The percent by mass of H2O in the compound is (0.135 g / 0.985 g) x 100% ≈ 13.7%.
1000 mg in a gram. Therefore .001 g in a mg. 6 mg is .006 grams.
if that's supposed to be .001 km then yes if not then no
.001
.001 m3
.138
True
p = 0.001
.001 mg
1 milimetre = .001 or 10^-3 metres. 58 metres / .001 = 58,000 milimetres.
One kilometre is 1000 metres.
1 meter = .001 km
.oo1 gram (g) = 1 milligram (mg)