It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell. It what happens when elements don't obey the octect rule, i.e. elements that have more than eight electrons in their outermost shell.
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Elements with more than eight valence electrons (expanded octet) or less than eight valence electrons (incomplete octet) can violate the octet rule. Examples include elements in the third period or below in the Periodic Table such as phosphorus, sulfur, and chlorine. Additionally, transition metals and elements with vacant d orbitals can also violate the octet rule.
Potentially elements above neon in the periodic table, as these have d orbitals and te hevier ones f orbitals . In practise exclude the group 1,2 elements. The "expansion" of the octet is common it is a rule but in inorganic chemistry all rules are made to be broken even this one. P.S don't forget Hydrogen that obeys the duet rule (Helium configuration)!
The octet rule is a chemistry rule or guideline. It is states that when an atom is low in atomic number it will behave a certain way. If it doesnÕt follow the rule then is a standard atom.
CF4 and XeF4 do not violate the octet rule. In CF4, carbon forms four covalent bonds with fluorine, fulfilling the octet rule. In XeF4, xenon forms four covalent bonds with fluorine and has two lone pairs, also satisfying the octet rule.
Yes, both Cu+ and Cu2+ violate the octet rule. Copper (Cu) is an exception to the octet rule due to its electron configuration, which allows it to have a partially filled d orbital. This leads to Cu forming compounds where it does not achieve a full octet of electrons.
The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
Molecules that do not violate the octet rule include hydrogen (H2), beryllium (BeCl2), and boron (BCl3). These molecules satisfy the octet rule by having less than eight electrons around the central atom.
Yes, the element sulfur in SO3 violates the octet rule because it has more than 8 electrons in its valence shell.