Platinum is a noble metal and is resistant to most chemical reactions, including with lead(II) nitrate solution. So, platinum will not react with lead(II) nitrate solution.
The chemical formula of lead(II) nitrate is Pb(NO3)2. The solution don't change the formula - but in the solution exist the anion (NO3)- and the cation Pb2+.
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
To separate a mixture of iodine and lead(II) nitrate, you can first dissolve the mixture in water to form a solution. Then, you can use techniques such as filtration or precipitation to separate the components. Lead(II) nitrate will precipitate out as a solid, while iodine remains in solution. You can then filter the solid lead(II) nitrate from the solution to isolate the two components.
Lead(II) nitrate, chemical formula Pb(NO3)2.It commonly occurs as a colourless crystal or white powder and is soluble in water giving a clear, colorless solution.
Lead (II) nitrate solution is colorless.
Lead compounds tend to be blue in flame tests
Platinum is a noble metal and is resistant to most chemical reactions, including with lead(II) nitrate solution. So, platinum will not react with lead(II) nitrate solution.
The chemical formula of lead(II) nitrate is Pb(NO3)2. The solution don't change the formula - but in the solution exist the anion (NO3)- and the cation Pb2+.
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
To separate a mixture of iodine and lead(II) nitrate, you can first dissolve the mixture in water to form a solution. Then, you can use techniques such as filtration or precipitation to separate the components. Lead(II) nitrate will precipitate out as a solid, while iodine remains in solution. You can then filter the solid lead(II) nitrate from the solution to isolate the two components.
Lead(II) nitrate, chemical formula Pb(NO3)2.It commonly occurs as a colourless crystal or white powder and is soluble in water giving a clear, colorless solution.
When Zinc nitrate solution is added to Lead nitrate solution, a white precipitate of Lead(II) nitrate will form. This is because Lead(II) nitrate is insoluble in water. The Zinc nitrate solution will remain in the mixture as it is soluble in water.
This solution is almost without color.
First, calculate the number of moles of nitrate ions in lead(II) nitrate: 0.027823 mol lead(II) nitrate * 2 mol nitrate ions / 1 mol lead(II) nitrate = 0.055646 mol nitrate ions. Then, calculate the molar concentration: 0.055646 mol nitrate ions / 0.8 L = 0.0696 M nitrate ions in the solution.
The reaction that occurs is a double displacement reaction where lead(II) nitrate and potassium iodide switch partners to form solid lead(II) iodide and potassium nitrate solution. This reaction can be represented by the equation Pb(NO3)2 + 2KI -> Pbl2 + 2KNO3.
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.