When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
The particle with a -3 charge and 36 electrons is an ion of the element phosphorus (P). It has gained three extra electrons, resulting in a charge of -3.
The particle is an atom of selenium (Se). It has 34 protons and 34 electrons, since the number of protons equals the number of electrons in a neutral atom. The electron configuration given ("1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6") matches that of selenium.
We usually see p+ used for the proton. Remember that it's a hydrogen nucleus. It might appear as H+ to denote a hydrogen atom (actually an ion) that has lost its electron and is a lonely proton with its characteristic +1 charge. Note that a hydrogen nucleus can sometimes have one or even two neutrons stuck together with the proton. Just so ya know. Also, it can be written as 1 over 1 p
The sub atomic particles to an atom are the proton (p), neutron (n). The p and n both contribute to atomic mass. The positive charge comes from the p and outside the atom in orbit is/are the electron with negligible mass, but negative charge.
It has one nucleon it has no neutrons it has one proton
p
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Proton.
I am assuming that this is to do with the trajectory that is simplified to that of a particle which does not incur air resistance. If I have understood the question correctly, the particle travels under the influence of a constant force - assumed to be gravity which acts downwards. The model can be extended to allow for a constant force acting at an angle but the calculations then become more complicated. The particle is projected upwards, with the initial velocity, u ms-1, which makes an angle P with the horizontal. u is a variable such that the horizontal range of the particle is a constant. The vertical component of the initial velocity is u*sin(P) ms-1. The gravitational force, acting downwards, is -g ms-2. When the particle returns to the ground level, the vertical component of its velocity is -u*sin(P) ms-1. So if the particle returns at time t seconds, then t = [u*sin(P) - -u*sin(P)] /g = 2*u*sin(P)/g sec. The horizontal component of the velocity of the particle is a constant u*cos(P) ms-1. So during the time in flight, it travels u*cos(P)*2*u*sin(P)/g m = 2*u2*sin(P)*cos(P)/g m. This horizontal distance is constant, which implies that 2*u2*sin(P)*cos(P)/g is constant so that u2 is inversely proportional to sin(P)*cos(P). So let u = sqrt[k/sin(P)*cos(P)] ms-1 for some constant k. then its vertical component is u*sin(P) = sqrt[k/sin(P)*cos(P)]*sin(P) ms-1 = sqrt[k*tan(P)] Then at time T, its height is sqrt[k*tan(P)]*T - 0.5g*T2 I just hope this is correct!
The answer is 1/90.
When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
Particle
A gamma ray is not an elementary particle, it is a high-energy photon. Photons are elementary particles that have zero rest mass and carry electromagnetic radiation.
particle
Particle velocityparticle displacementpolarizationpressureplasmas
Particle.