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1-it is a white solid. 2-it is a crystalline compound. 3-it is hygroscopic solid. 4-it is a strong base. 5-it forms salts with acids .6- it turns red litmus blue. 7- it turns phenolphthalein solution pink..........

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12y ago
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6mo ago

Potassium hydroxide (KOH) is a white solid at room temperature and is highly soluble in water. It is a strong base that is corrosive and can cause severe burns upon contact with skin. KOH is commonly used in the manufacturing of soaps, detergents, and various other chemical products.

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Q: What are the properties of KOH?
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What is the formula for the ionic compound from potassium hydroxide?

The formula for the ionic compound formed from potassium hydroxide is KOH. This is because potassium (K) has a +1 charge and hydroxide (OH) has a -1 charge, so they combine in a 1:1 ratio to form a neutral compound.


How do you prepare 0.5N KOH solution?

To prepare a 0.5N KOH solution, dissolve 20.4 grams of KOH pellets in enough distilled water to make 1 liter of solution. This will give you a solution with a normality (N) of 0.5. Be sure to wear appropriate safety gear and handle KOH with care due to its caustic properties.


Name for koh?

KOH is potassium hydroxide.


Is it true that 1M KOH equals 1M C7O2H7?

No, 1M KOH (potassium hydroxide) does not equal 1M C7O2H7 (pimelic acid). They have different chemical formulas and properties, so their molarities cannot be equated in general chemical reactions or calculations.


How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?

The answer is 12,831 g KOH.


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What is the conjugate acid KOH?

The conjugate acid of KOH is H2O, which is formed when KOH accepts a proton (H+).


How many moles are in 234.1 grams of KOH?

To find the number of moles in 234.1 grams of KOH, first calculate the molar mass of KOH (39.1 g/mol for K, 16.0 g/mol for O, and 1.0 g/mol for H). Add up the molar masses to get 56.1 g/mol for KOH. Divide the given mass (234.1 g) by the molar mass (56.1 g/mol) to find that there are approximately 4.17 moles of KOH in 234.1 grams.


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