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What are the oxidation numbers of the atoms in the MnO4- ion?

Anonymous

∙ 12y ago

Updated: 5/23/2024

+7 for Mn

-2 for each O

Wiki User

∙ 12y ago

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More answers

For the MnO4- ion, the oxidation number of oxygen is typically -2. Since the overall charge of the ion is -1, the oxidation number of manganese (Mn) must be +7 to balance out the charges.

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Oxidation number of mn in mno4-?

The oxidation number of Mn in MnO4- is +7. This is determined by balancing the charge of the whole ion (-1) with the charges of the oxygen atoms (-8) and solving for the oxidation number of Mn.

What is the oxidation number of O in MnO4?

The oxidation number of oxygen (O) in MnO4 is -2. To find the oxidation number of manganese (Mn) in MnO4, we use the fact that the sum of the oxidation numbers in a compound is zero (since MnO4 is a polyatomic ion). Therefore, Mn must have an oxidation number of +7 in this compound.

What is the oxidation number of MN in 2MnO4-?

I assume you mean the oxidation number of Mn in the permanganate ion , MnO4- The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.

In a polyatomic ion the algebraic sum of the oxidation numbers of all atoms is equal to?

The algebraic sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the overall charge of the ion.

In a polyatomic ion the algebraic sum of all the oxidation numbers of all atoms equal to?

the charge on that ion

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Related Questions

Oxidation number of mn in mno4-?

The oxidation number of Mn in MnO4- is +7. This is determined by balancing the charge of the whole ion (-1) with the charges of the oxygen atoms (-8) and solving for the oxidation number of Mn.

What is the oxidation number of O in MnO4?

The oxidation number of oxygen (O) in MnO4 is -2. To find the oxidation number of manganese (Mn) in MnO4, we use the fact that the sum of the oxidation numbers in a compound is zero (since MnO4 is a polyatomic ion). Therefore, Mn must have an oxidation number of +7 in this compound.

What is the oxidation number of MN in 2MnO4-?

I assume you mean the oxidation number of Mn in the permanganate ion , MnO4- The sum of the oxidation numbers is the charge on a polyatomic ion so Mn has an oxidation number of +7 as each O is assigned -2.

In a polyatomic ion the algebraic sum of the oxidation numbers of all atoms is equal to?

The algebraic sum of the oxidation numbers of all atoms in a polyatomic ion is equal to the overall charge of the ion.

In a polyatomic ion the algebraic sum of all the oxidation numbers of all atoms equal to?

the charge on that ion

What is the sum of the oxidation numbers in the phosphate ion?

The sum of the oxidation numbers in the phosphate ion (PO4^3-) is -3. Each oxygen atom has an oxidation number of -2, totaling -8. The oxidation number for phosphorus is +5 to offset the oxygen atoms and give a total charge of -3 for the ion.

What is the oxidation numbers of manganese in MnO4 1-?

The oxidation number of manganese in MnO4 1- is +7. Each oxygen atom has an oxidation number of -2, and the overall charge of the ion is -1. Therefore, the oxidation number of manganese can be calculated as +7 to balance the charges.

How to solve for the oxidation number of charge of a polyatomic ion?

To find the oxidation number or charge of a polyatomic ion, consider the known charges of the individual atoms within the ion. For example, in the sulfate ion (SO4)2-, oxygen typically has an oxidation number of -2, and sulfur would then have an oxidation number to balance the charge of the ion. The sum of the oxidation numbers of all the atoms in the ion should equal the overall charge of the ion.

What is the oxidation number of MnO42-?

The oxidation number of manganese (Mn) in MnO4^2- is +7. Oxygen typically has an oxidation number of -2. To find the overall charge of the ion, we can use the formula: Charge = oxidation number of Mn + 4(oxidation number of O) + 2 (charge of the ion) = 0 Substitute in the known values, we get: Charge = +7 + 4(-2) + 2 = 0 Therefore, the oxidation number of Mn in MnO4^2- is +7.

What is the permanganate ion composed of?

The permanganate ion is composed of one manganese atom (Mn) surrounded by four oxygen atoms (O) bonded together. The chemical formula of the permanganate ion is MnO4-.

What are the rules to follow in assigning an oxidation number?

In a neutral compound, the sum of oxidation numbers of all atoms will be zero. In a polyatomic ion, the sum of oxidation numbers of all atoms will be equal to the charge of the ion. The oxidation number of an element in its elemental form is zero. Fluorine always has an oxidation number of -1 in compounds. Oxygen usually has an oxidation number of -2 in compounds.

What is the oxidation number of MnO4?

The oxidation number of Mn in MnO4 is +7. This is because oxygen is almost always assigned an oxidation number of -2, so the total oxidation number for the entire MnO4 ion must be -1. Since there is one Mn atom in MnO4, the oxidation number of Mn must be +7 to make the total -1 charge balance out.

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