In an electrolytic cell with aluminum and gold, the half-reaction for the oxidation of aluminum is: Al(s) -> Al^3+(aq) + 3e^-. The half-reaction for the reduction of gold is: Au^3+(aq) + 3e^- -> Au(s). These half-reactions represent the flow of electrons during the electrolysis process, with aluminum being oxidized and gold being reduced.
the gold metal
In an electrolytic cell with aluminum and gold electrodes, aluminum would be oxidized at the anode. This is because aluminum has a higher tendency to lose electrons compared to gold, making it more likely to undergo oxidation.
No, gold is denser than aluminum. Gold has a density of 19.32 g/cm^3, while aluminum has a density of 2.70 g/cm^3.
Aluminum has a lower density than gold, meaning the same mass of aluminum takes up more space compared to gold. Therefore, a kilogram of aluminum will occupy more volume than a kilogram of gold due to the difference in their densities.
Yes, aluminum is more reactive than gold. Aluminum is more prone to oxidation and reacts readily with oxygen in the air, whereas gold is a noble metal and does not easily react with other elements.
the gold metal
the gold metal
In an electrolytic cell with aluminum and gold electrodes, aluminum would be oxidized at the anode. This is because aluminum has a higher tendency to lose electrons compared to gold, making it more likely to undergo oxidation.
Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)
The aluminum metals
The answer is not c.
The aluminum metals
A.) Solid gold will form. B.) Aluminum will be oxidized
Al(s) Al3+(aq) + 3e- and Au+(aq) + e- Au(s)
bluewater or westfield
how to convert aluminum in to gold
Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-