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Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-

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Emie Howe

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βˆ™ 3y ago
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AnswerBot

βˆ™ 5mo ago

At the cathode: 2Au^3+ + 6e^- -> 2Au
At the anode: 2Al -> 2Al^3+ + 6e^-

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βˆ™ 14y ago

C. Fe3+(aq) + e- -> Fe2+(aq) and Al(s) -> Al3+(aq) + 3e-

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βˆ™ 14y ago

Fe3+(aq) + e- → Fe2+(aq) and Al(s) → Al3+(aq) + 3e-

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Q: What are half reactions for an electrolytic cell with aluminum and gold?
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Related questions

What is oxidized and electrolytic cell with aluminum and gold electrodes?

the gold metal


What is oxidation in an electrolytic cell with aluminum and gold electrodes?

the gold metal


What is oxidized in an electolytic cell with aluminum and gold electrodes?

In an electrolytic cell with aluminum and gold electrodes, aluminum would be oxidized at the anode. This is because aluminum has a higher tendency to lose electrons compared to gold, making it more likely to undergo oxidation.


What is the standard cell notation for an electrolytic cell with an aluminum and gold electrodes?

Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)


What is oxidation in a galvanic cell with aluminum and gold electrodes?

The aluminum metals


Which of the following is an electrolytic cell A. lron * (ll) * (Fe) oxidized, aluminum (Al) reduced O B. Silver (Ag) oxidized, gold (Au) reduced C. Aluminum () oxidized (Zn) reduced LithiumD. (Li) oxidized, (Zn) reduced?

The answer is not c.


What is oxidized in galvanic cell with aluminum and gold electrode?

The aluminum metals


What will be true if gold and aluminum are used to form an electrochemical cell?

A.) Solid gold will form. B.) Aluminum will be oxidized


What are the half-reactions for a galvanic cell with aluminum and gold electrodes?

Al(s) Al3+(aq) + 3e- and Au+(aq) + e- Au(s)


Where can you get a electrolytic conductor for removing of gold?

bluewater or westfield


How do you aluminum convert in to gold?

how to convert aluminum in to gold


What are the half reaction for an electrolytic cell with aluminum and gold electrodes?

Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-