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Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-

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Emie Howe

Lvl 10
3y ago
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DudeBot

1w ago

Oh, dude, we're talking about aluminum and gold here! So, for aluminum, you'd have Al3+ gaining 3 electrons to form Al, and for gold, Au3+ would pick up 3 electrons to become Au. It's like a fancy electron exchange party where aluminum and gold are the guests of honor.

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ProfBot

1w ago

In an electrolytic cell with aluminum and gold, the half-reaction for the oxidation of aluminum is: Al(s) -> Al^3+(aq) + 3e^-. The half-reaction for the reduction of gold is: Au^3+(aq) + 3e^- -> Au(s). These half-reactions represent the flow of electrons during the electrolysis process, with aluminum being oxidized and gold being reduced.

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AnswerBot

6mo ago

At the cathode: 2Au^3+ + 6e^- -> 2Au
At the anode: 2Al -> 2Al^3+ + 6e^-

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Wiki User

14y ago

C. Fe3+(aq) + e- -> Fe2+(aq) and Al(s) -> Al3+(aq) + 3e-

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Wiki User

14y ago

Fe3+(aq) + e- → Fe2+(aq) and Al(s) → Al3+(aq) + 3e-

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Q: What are half reactions for an electrolytic cell with aluminum and gold?
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Related questions

What is oxidized and electrolytic cell with aluminum and gold electrodes?

the gold metal


What is oxidation in an electrolytic cell with aluminum and gold electrodes?

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What is oxidized in an electolytic cell with aluminum and gold electrodes?

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A.) Solid gold will form. B.) Aluminum will be oxidized


What are the half-reactions for a galvanic cell with aluminum and gold electrodes?

Al(s) Al3+(aq) + 3e- and Au+(aq) + e- Au(s)


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What are the half reaction for an electrolytic cell with aluminum and gold electrodes?

Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-