HBr is not a weak base; it is a strong acid. In water, HBr completely dissociates into H+ and Br- ions, leading to a high concentration of H+ ions in solution. This strong acidity makes HBr a poor proton acceptor and hence not a base.
HBr is a strong acid. It dissociates completely in water to form H+ and Br- ions, making it a strong acid rather than a base.
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
HBrO is a weak acid. It can donate a proton in solution, which classifies it as acidic.
There is no conjugate) base coupled to bromide, Br-, because this Br- can NOT donate (by protolysing) a proton (H+) in water.However Br- itself is the very, very weakest base of the (very, very) strong conjugate acid HBr.This is the only possible conjugate acid/base pair:HBr/Br-
HBr is not a weak base; it is a strong acid. In water, HBr completely dissociates into H+ and Br- ions, leading to a high concentration of H+ ions in solution. This strong acidity makes HBr a poor proton acceptor and hence not a base.
No, HBr and NaBr cannot function as a buffer system because HBr is a strong acid and NaBr is a salt of a strong acid and strong base, therefore they do not have the necessary components to maintain a constant pH. Buffers typically consist of a weak acid and its conjugate base or a weak base and its conjugate acid to resist changes in pH.
HBr is a strong acid. It dissociates completely in water to form H+ and Br- ions, making it a strong acid rather than a base.
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
If phenolphthalein is added to HBr (hydrobromic acid), which is a strong acid, the phenolphthalein indicator will remain colorless because it only changes color in the presence of a base. Since HBr is an acid, it will not cause the indicator to change color.
HBrO is a weak acid. It can donate a proton in solution, which classifies it as acidic.
There is no conjugate) base coupled to bromide, Br-, because this Br- can NOT donate (by protolysing) a proton (H+) in water.However Br- itself is the very, very weakest base of the (very, very) strong conjugate acid HBr.This is the only possible conjugate acid/base pair:HBr/Br-
HBr is an acid. It gives hydroxonium ions and bromide ions when dissolving in water.
Yes, HBr is a strong acid. When it dissolves in water, it releases hydrogen ions (H+) which make it acidic.
because it is a strong acid
KBr is not a base, but a salt formed by the combination of the strong base KOH and the strong acid HBr. It is considered a neutral salt since it does not significantly contribute to the pH of a solution.
HNO2 does not behave as a strong acid when dissolved in water. It is a weak acid, whereas HBr, HCl, and HClO4 are strong acids.