BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
The reaction between barium chromate (BaCrO4) and hydrochloric acid (HCl) produces barium chloride (BaCl2), chromium(III) chloride (CrCl3), and water (H2O). The balanced chemical equation for this reaction is: BaCrO4 (s) + 2HCl (aq) -> BaCl2 (aq) + CrCl3 (aq) + H2O
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
The chemical formula for chromic bisulfate is Cr2(SO4)3.
The opposite of the colour purple on a colour wheel is yellow. To figure this out you need to understand the concept of primary and secondary colours. If the colour you have is a primary colour (one of red, yellow or blue) then the opposite colour is the secondary colour resultant from mixing the two remaining primary colours. If the colour you have is a secondary (purple, green or orange) then the opposite colour is the primary not involved in the making of the secondary colour.
The formula for Barium chromate is BaCrO4.
Yes, BaCrO4 is a solid compound. It is a yellow crystalline powder that is insoluble in water.
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
Barium chromate (BaCrO4) has low solubility in water, with a solubility product constant (Ksp) of 1.2 x 10^-10 at 25°C. This means that only a small amount of BaCrO4 will dissolve in water, resulting in a saturated solution.
Barium Chromate = BaCrO4
The reaction between barium chromate (BaCrO4) and hydrochloric acid (HCl) produces barium chloride (BaCl2), chromium(III) chloride (CrCl3), and water (H2O). The balanced chemical equation for this reaction is: BaCrO4 (s) + 2HCl (aq) -> BaCl2 (aq) + CrCl3 (aq) + H2O
Ba = 137.327Cr = 51.9961O = 15.9994BaCrO4 = 137.327 + 51.9961 + 4(15.9994) =253.3207 g/mol51.9961 / 253.3207 = 0.205260.20526 x 100 = 20.526The answer is:20.526%
The balanced equation for the reaction between barium chloride (BaCl2) and sodium chromate (Na2CrO4) is: BaCl2 + Na2CrO4 -> BaCrO4 + 2NaCl
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
The chemical formula for chromic bisulfate is Cr2(SO4)3.
K2CrO4(aq) + Ba(NO3)2(aq) -> BaCrO4(s) + 2KNO3(aq) is a double displacement reaction.
The molecular weight of Barium Chromate (BaCrO4) is 253.37.Therefore, one Gram Mole weighs 253.37 grams.When handling this chemical REMEMBER, it is Poisonous!