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The van't Hoff factor for sodium sulfate (Na2SO4) is 3, as it dissociates into 3 ions in solution: 2 Na+ ions and 1 SO4^2- ion.
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What is the vant Hoff factor for NaCl if it completely dissociates in water?
The vant Hoff factor for NaCl is 2, as it completely dissociates into Na+ and Cl- ions in water, resulting in two ions formed per formula unit of NaCl.
Vant's hoff factor of ca NO3 2?
Oh, dude, Vant Hoff factor is basically the number of particles a compound breaks into in a solution. So, for Ca(NO3)2, it's like, "Ca" is calcium, and "NO3" is nitrate, right? So, it's gonna break into three particles - one calcium ion and two nitrate ions. So, the Vant Hoff factor for Ca(NO3)2 is 3. Easy peasy, lemon squeezy!
What is the vant Hoff factor of MgSO4 for Ki solution at a freezing-point depression of a 0.100 m MgSO4 in 0.225 Celsius?
The van't Hoff factor of MgSO4 is 3, as it dissociates into three ions: Mg2+ and 2SO4^2-. For a freezing-point depression, we need to use the equation ΞT = iKfm, where i is the van't Hoff factor, Kf is the cryoscopic constant, and m is the molality of the solution. By rearranging the equation, we can solve for i, which would be 3 in this case.
What is the vant Hoff factor for NaCl if it completely dissociates in water?
The vant Hoff factor for NaCl is 2, as it completely dissociates into Na+ and Cl- ions in water, resulting in two ions formed per formula unit of NaCl.
Vant's hoff factor of ca NO3 2?
Oh, dude, Vant Hoff factor is basically the number of particles a compound breaks into in a solution. So, for Ca(NO3)2, it's like, "Ca" is calcium, and "NO3" is nitrate, right? So, it's gonna break into three particles - one calcium ion and two nitrate ions. So, the Vant Hoff factor for Ca(NO3)2 is 3. Easy peasy, lemon squeezy!
What is the vant Hoff factor of MgSO4 for Ki solution at a freezing-point depression of a 0.100 m MgSO4 in 0.225 Celsius?
The van't Hoff factor of MgSO4 is 3, as it dissociates into three ions: Mg2+ and 2SO4^2-. For a freezing-point depression, we need to use the equation ΞT = iKfm, where i is the van't Hoff factor, Kf is the cryoscopic constant, and m is the molality of the solution. By rearranging the equation, we can solve for i, which would be 3 in this case.
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