0
The equilibrium constant for the reaction below is 31.25 at equilibrium so2 0.03 o2 0.05 and h2s 0.15 what is the equilibrium concentration of H2O?
The equilibrium constant expression for the reaction is Kc = [H2O]^2/[SO2][O2]. Given the concentrations at equilibrium, we can solve for [H2O]. Plugging in the values, we get 31.25 = [H2O]^2 / (0.03)(0.05). Solving for [H2O] gives us [H2O] = sqrt(31.25 * 0.03 * 0.05), which is approximately 0.275M.
Add your answer:
Earn +20 pts
The equilibrium constant for the reaction below is 0.625. At equilibriumO 2 0.40 and H2O 0.20. What is the equilibrium concentration of H2O2?
Given the equilibrium constant (Kc) is 0.625 and the concentrations of O2 and H2O at equilibrium are 0.40 and 0.20 respectively, you can use the equilibrium expression Kc = [H2O2] / ([O2] * [H2O]) to solve for the equilibrium concentration of H2O2. Plugging in the values, you can calculate the concentration of H2O2 at equilibrium.
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.15 H2O equals 0.21 O2 equals 0.25 What is the equilibrium constant for this reaction?
The equilibrium constant (Kc) for the reaction would be [O2]/([H2O2]^[H2O]) = 0.25/(0.15*0.21) = 7.94
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.37 H2O equals 0.24 O2 equals 0.92 What is the equilibrium constant for this reaction?
The equilibrium constant (Kc) for a reaction can be calculated using the concentrations of the products and reactants at equilibrium. In this case, Kc = [O2]/([H2O]^2). Plugging in the given values, Kc = (0.92)/((0.37)^2) ≈ 6.56.
How is the rate constant related to concentration of reactants?
The rate constant is independent of the concentration of reactants. It is a constant that reflects the intrinsic characteristics of the reaction. The rate of reaction, on the other hand, is directly proportional to the concentration of reactants raised to the power of their respective stoichiometric coefficients.
Why half life of first order reaction does not depend upon the concentration?
The half-life of a first-order reaction is constant because it is based on the rate constant, which is independent of the initial concentration of the reactant. In a first-order reaction, the rate of the reaction is directly proportional to the concentration of the reactant, so as the concentration decreases, the rate of reaction also decreases to maintain a constant half-life period.
The equilibrium constant for the reaction below is 0.49 At equilibrium O2 equals 0.11 and N2 equals 0.15 What is the equilibrium concentration of NO?
To find the equilibrium concentration of NO, first calculate the equilibrium constant expression using the given concentrations of O2 and N2. Then, rearrange the equilibrium constant expression to solve for the concentration of NO. Finally, substitute the values of O2 and N2 concentrations into the rearranged expression to find the equilibrium concentration of NO.
The equilibrium constant for the reaction below is 0.625. At equilibriumO 2 0.40 and H2O 0.20. What is the equilibrium concentration of H2O2?
Given the equilibrium constant (Kc) is 0.625 and the concentrations of O2 and H2O at equilibrium are 0.40 and 0.20 respectively, you can use the equilibrium expression Kc = [H2O2] / ([O2] * [H2O]) to solve for the equilibrium concentration of H2O2. Plugging in the values, you can calculate the concentration of H2O2 at equilibrium.
The equilibrium constant for the reaction below is 0.625 At equilibrium O2 0.40 and H2O 0.20 What is the equilibrium concentration of H2O2?
The reaction is: 2H2O2(l) -> 2H2O(l) + O2(g). Using the equilibrium constant expression K = [O2]^2 / [H2O2]^2, you can substitute the given values to calculate [H2O2]. Rearranging the equation gives [H2O2] = sqrt([O2]^2 / K) = sqrt(0.40^2 / 0.625) = 0.32 mol/L. Thus, the equilibrium concentration of H2O2 is 0.32 mol/L.
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.15 H2O equals 0.21 O2 equals 0.25 What is the equilibrium constant for this reaction?
The equilibrium constant (Kc) for the reaction would be [O2]/([H2O2]^[H2O]) = 0.25/(0.15*0.21) = 7.94
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.55 H2O equals 0.75 O2 equals 0.15 What is the equilibrium constant for this reaction?
0.28
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.05 H2O equals 0.11 O2 equals 0.07 What is the equilibrium constant for this reaction?
0.34
The reaction shown below reaches equilibrium with the concentrations H2O2 equals 0.37 H2O equals 0.24 O2 equals 0.92 What is the equilibrium constant for this reaction?
The equilibrium constant (Kc) for a reaction can be calculated using the concentrations of the products and reactants at equilibrium. In this case, Kc = [O2]/([H2O]^2). Plugging in the given values, Kc = (0.92)/((0.37)^2) ≈ 6.56.
The equlibrium constant for the reaction below is 0.62 At equlibrium O2 equals 0.40 and H2O equals 0.20 What is the equlibrum concentration of H2O2?
Using the equilibrium constant expression, (K = \frac{[products]}{[reactants]}), we can set up the equation as (0.62 = [H2O2] / ([O2] * [H2O])). Plugging in the given values, we get (0.62 = [H2O2] / (0.4 * 0.2)). Solving for [H2O2], we find the equilibrium concentration of H2O2 to be 0.62 * 0.4 * 0.2 = 0.0492.
How is the rate constant related to concentration of reactants?
The rate constant is independent of the concentration of reactants. It is a constant that reflects the intrinsic characteristics of the reaction. The rate of reaction, on the other hand, is directly proportional to the concentration of reactants raised to the power of their respective stoichiometric coefficients.
The reaction shown below reaches equilibrium with the concentrations CO2 equals 0.15 CO equals 0.03 O2 equals 0.05 What is the equilibrium constant for this reaction?
H2(g) + I2(g) 2HI(g)18.6
What is the equilibrium for the reaction below C(s)+o2(g) co2(g)?
96
Why half life of first order reaction does not depend upon the concentration?
The half-life of a first-order reaction is constant because it is based on the rate constant, which is independent of the initial concentration of the reactant. In a first-order reaction, the rate of the reaction is directly proportional to the concentration of the reactant, so as the concentration decreases, the rate of reaction also decreases to maintain a constant half-life period.
