The oxidation number of Cr in CrO5 is +6. This can be calculated by assigning oxygen an oxidation number of -2 (since it usually has an oxidation number of -2 in compounds), and then solving for Cr. Each oxygen atom contributes -2, giving a total of -10. To balance the charge of the compound, Cr must have an oxidation number of +6.
+2 for Ca, +6 for Cr, -2 for each O
The oxidation number for Cr in Cr2O7^2- is +6.
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
+3 for Cr and -2 for O
The oxidation number of Cr in CrBr is +3. Since Br has an oxidation number of -1 and there is only one Br atom in the compound, the oxidation number of Cr must be +3 to balance the charges to zero.
Hi, CrO5 is a compound which has the structure which has peroxide linkage(O2 2-) as shown: Thus the oxidation number of Chromium can be calculated as : Let the oxidation number of Cr be x, then x-2-2(2)=0 x-2-4=0 x-6=0 thus x=+6
+2 for Ca, +6 for Cr, -2 for each O
The oxidation number for Cr in Cr2O7^2- is +6.
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
+3 for Cr and -2 for O
The oxidation number of Cr in CrBr is +3. Since Br has an oxidation number of -1 and there is only one Br atom in the compound, the oxidation number of Cr must be +3 to balance the charges to zero.
The oxidation number of Cr in MgCrO4 is +6. This is because oxygen is typically assigned an oxidation number of -2, and the overall charge of the compound is 0, so the oxidation number of magnesium (+2) and oxygen (-2) must be balanced by the oxidation number of Cr (+6).
The oxidation number of chromium (Cr) in CrO4^2- is +6. Since each oxygen atom has an oxidation number of -2, and the overall charge of the polyatomic ion is -2, the oxidation number of chromium can be determined by solving the equation: (oxidation number of Cr) + 4(-2) = -2.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number for Cr in CrPO4 is +3. This is because the overall charge of the compound is neutral, and the oxidation numbers for oxygen (-2) and phosphorus (+5) are known. By calculation, we determine the oxidation number of Cr to be +3.
As with any other element, the oxidation number of Cr depends on whether and how it is chemically bonded. The oxidation number of pure elements is arbitrarily defined to be 0. In compounds, Cr has oxidation numbers of +2, +3, and +6, depending on the compound.