The formula of magnesium carbonate is MgCO3. It therefore has one atom each of magnesium and carbon and 3 atoms of oxygen. The gram molecular weight is therefore
24.305 + 12.011 + 3(15.999) = 84.313. This answer to the problem is twice this value, 168.626 grams, if the number "two" is considered to be exact.
For this you need the atomic (molecular) mass of MgCl2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. MgCl2= 95.3 grams
2.00 moles MgCl2 × (95.3 grams) = 190.6 grams MgCl2
To determine the number of formula units in 2.5 grams of Magnesium Chloride, you first need to calculate the molar mass of the compound (MgCl2). Then, use this molar mass to convert the grams of Magnesium Chloride to moles. Finally, use Avogadro's number (6.022Γ10^23) to find the number of formula units in the given amount of Magnesium Chloride.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
To calculate the mass of magnesium chloride formed, you first need to write the balanced chemical equation for the reaction between HCl and magnesium to form magnesium chloride. Then, calculate the molar mass of HCl and magnesium chloride. Next, determine the number of moles of HCl using its molar mass and the given mass, and use the stoichiometry from the balanced equation to find the number of moles of magnesium chloride formed. Finally, calculate the mass of magnesium chloride using its molar mass and the number of moles.
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol β 4.66 moles of magnesium chloride.
To determine the number of formula units in 2.5 grams of Magnesium Chloride, you first need to calculate the molar mass of the compound (MgCl2). Then, use this molar mass to convert the grams of Magnesium Chloride to moles. Finally, use Avogadro's number (6.022Γ10^23) to find the number of formula units in the given amount of Magnesium Chloride.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
To calculate the molarity, first determine the molar mass of magnesium chloride, which is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Next, calculate the number of moles of magnesium chloride in 128 grams by dividing the mass by the molar mass. Then, divide the moles by the volume of the solution in liters to get the molarity. So, the molarity of the solution would be about 1.34 M.
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
The molar mass of ammonium chloride (NH4Cl) is approximately 53.49 g/mol. To find the mass of 3 moles, multiply the molar mass by the number of moles: 3 moles x 53.49 g/mol = 160.47 grams of ammonium chloride.
To calculate the mass of magnesium chloride formed, you first need to write the balanced chemical equation for the reaction between HCl and magnesium to form magnesium chloride. Then, calculate the molar mass of HCl and magnesium chloride. Next, determine the number of moles of HCl using its molar mass and the given mass, and use the stoichiometry from the balanced equation to find the number of moles of magnesium chloride formed. Finally, calculate the mass of magnesium chloride using its molar mass and the number of moles.
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
1,11 moles of magnesium have 26,97855 g.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
To find the number of chloride atoms in 654.5 grams of calcium chloride, you would first calculate the number of moles of calcium chloride using its molar mass. Then, since each formula unit of calcium chloride contains two chloride ions, you would multiply the number of moles by 2 to find the number of chloride atoms.