There are 1.81 x 10^24 atoms in 3.00 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
There are approximately ( 2.84 \times 10^{24} ) atoms in 4.7 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.
To determine the number of Li atoms in 97.9 g of Li, you first need to calculate the number of moles of Li using the molar mass of Li (6.94 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of Li to atoms.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
To find the number of atoms in 55.2 grams of lithium (Li), you need to first determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, use this value to convert the grams of lithium to moles. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in 55.2 grams of lithium.
There are 1.81 x 10^24 atoms in 3.00 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
To find the number of moles of Li atoms in 10.56g of Li, you need to divide the given mass by the molar mass of Li (6.94 g/mol). 10.56g / 6.94 g/mol = 1.52 moles of Li atoms.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
There are approximately ( 2.84 \times 10^{24} ) atoms in 4.7 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.
To determine the number of Li atoms in 97.9 g of Li, you first need to calculate the number of moles of Li using the molar mass of Li (6.94 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of Li to atoms.
1 mole of LiβO contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of LiβO, there are a total of 3 moles of atoms.
No moles of BaCO3 are found in any amount of Li.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
To find the number of atoms in 55.2 grams of lithium (Li), you need to first determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, use this value to convert the grams of lithium to moles. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in 55.2 grams of lithium.
3.977 mol
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li