Yes, when sulfuric acid is mixed with sodium hydroxide, a neutralization reaction occurs to form water and sodium sulfate. The color change that may occur will depend on the concentrations and purity of the substances being used. Generally, the reaction itself does not produce a noticeable color change.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
The symbol equation for sulfuric acid reacting with sodium hydroxide is: H2SO4 + 2NaOH -> Na2SO4 + 2H2O
Sulfuric acid is a strong acid.
The neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) can be represented by the following equation: H2SO4 + 2NaOH → Na2SO4 + 2H2O. In this reaction, sulfuric acid reacts with sodium hydroxide to form sodium sulfate and water.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
The symbol equation for sulfuric acid reacting with sodium hydroxide is: H2SO4 + 2NaOH -> Na2SO4 + 2H2O
Sulfuric acid is a strong acid.
The neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) can be represented by the following equation: H2SO4 + 2NaOH → Na2SO4 + 2H2O. In this reaction, sulfuric acid reacts with sodium hydroxide to form sodium sulfate and water.
The products of neutralization of sulfuric acid (H2SO4) and sodium hydroxide (NaOH) are water (H2O) and sodium sulfate (Na2SO4).
To neutralize the sulfuric acid completely, you need a 1:2 molar ratio of sodium hydroxide to sulfuric acid. Therefore, you would need to add twice the amount of sodium hydroxide compared to the amount of sulfuric acid, which is 40.0 mL of the sodium hydroxide solution.
The reaction of calcium hydroxide and sulfuric acid forms calcium sulfate and water, while the reaction of sodium hydroxide and sulfuric acid forms sodium sulfate and water. These differences occur because of the different chemical properties of calcium and sodium, leading to the formation of different products during the reactions.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
A base that can neutralize sulfuric acid is sodium hydroxide (NaOH). Sulfuric acid is a strong acid, so it requires a strong base like sodium hydroxide to neutralize it, forming water and sodium sulfate as the products.
The reaction between sodium hydroxide and sulfuric acid is called a neutralization reaction. In this reaction, sodium hydroxide (a base) reacts with sulfuric acid (an acid) to form water and sodium sulfate salt.
Sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH) to form sodium sulfate (Na2SO4) and water (H2O). The balanced equation is: H2SO4 + 2NaOH → Na2SO4 + 2H2O.