The oxidizing agent in this reaction is KNO3 (potassium nitrate). It provides the oxygen atoms needed for the oxidation reactions to occur.
The reaction between sulfuric acid (H2SO4) and potassium phosphate (K3PO4) will produce sulfuric acid and potassium sulfate. The balanced chemical equation for the reaction is: H2SO4 + K3PO4 -> H3PO4 + K2SO4
The reaction is:3 CuSO4 + 2 K3PO4 = Cu3(PO4)2 + 3 K2SO4The balanced molecular equation for copper(II) sulfate and potassium phosphate is:3CuSO4(aq) + 2K3PO4(aq) --> Cu3(PO4)2(s) + 3K2SO4(aq)This is a double replacement reaction, also called a double displacement reaction or a metathesis reaction. In this type of reaction, the positive and negative ions in the reactants switch places to form the products. The products must include a solid (precipitate), an insoluble gas that bubbles out of solution, or water. If none of those are present in the products, then their was no reaction. The general equation for a double replacement reaction is AB + CD --> AD + CB, in which A and C are the positive ions, and the B and D are the negative ions.
The balanced equation for copper sulfate (CuSO4) and potassium phosphate (K3PO4) reacting is: 3CuSO4 + 2K3PO4 -> Cu3(PO4)2 + 3K2SO4
The capital letter that represents a balanced chemical equation is "E".
The oxidizing agent in this reaction is KNO3 (potassium nitrate). It provides the oxygen atoms needed for the oxidation reactions to occur.
The reaction between sulfuric acid (H2SO4) and potassium phosphate (K3PO4) will produce sulfuric acid and potassium sulfate. The balanced chemical equation for the reaction is: H2SO4 + K3PO4 -> H3PO4 + K2SO4
The reaction is:3 CuSO4 + 2 K3PO4 = Cu3(PO4)2 + 3 K2SO4The balanced molecular equation for copper(II) sulfate and potassium phosphate is:3CuSO4(aq) + 2K3PO4(aq) --> Cu3(PO4)2(s) + 3K2SO4(aq)This is a double replacement reaction, also called a double displacement reaction or a metathesis reaction. In this type of reaction, the positive and negative ions in the reactants switch places to form the products. The products must include a solid (precipitate), an insoluble gas that bubbles out of solution, or water. If none of those are present in the products, then their was no reaction. The general equation for a double replacement reaction is AB + CD --> AD + CB, in which A and C are the positive ions, and the B and D are the negative ions.
The balanced equation for copper sulfate (CuSO4) and potassium phosphate (K3PO4) reacting is: 3CuSO4 + 2K3PO4 -> Cu3(PO4)2 + 3K2SO4
The capital letter that represents a balanced chemical equation is "E".
The balanced equation for Aluminum sulfate and Potassium Hydroxide is Al2(SO4)3 + 6KOH → 2Al(OH)3 + 3K2SO4.
This reaction may be misunderstood as a direct reaction between the thiosulphate and iodate ions , however, in practice an iodide and acid mediated production of iodine from the iodate is used to react with the thiosulphate. A standard reaction used to calibrate a solution of sodium thiosulphate is as follows: Acid and potassium iodide are added to a solution of potassium iodate getting the following reaction: KIO3 + 5KI + 3H2SO4 = 3I2 + 3K2SO4 + 3H2O represented by the following ionic equation: IO3- + 5I- + 6H+ = 3I2 + 3H2O Thiosulpathe is titrated against this solution (effectively against iodine): I2 + 2Na2S2O3 = Na2S4O6 + 2NaI represented by the following ionic equation: I2 + 2S2O32- = S4O62- + 2I- where the dark brown coloured solution of iodine turns pale yellow and finally colourless as the reaction proceeds (starch is used as indicator after the pale yellow transition forming a black solution due to an iodine-starch complex which turns colourless upon further addition of thiosulphate).
2Fe(SO4)3 + 6KOH ---> 2Fe(OH)3 + 3K2(SO4) iron 3 is +3, sulfate is -2, potasium is +1, and hydroxide is -1
Al2(SO4)3 + 6KOH --> 2 [Al(OH)3](s) + 3K2SO4or in excess hydroxide:Al2(SO4)3 + 8KOH --> 2K+ + 2 [Al(OH)4]-(aq) + 3K2SO4
Standardization of sodium thiosulfate uses potassium iodate with excess potassium iodide and acidified. Iodine is liberated and that is titrated with sodium thiosulfate. KIO3 + 5KI + 3H2SO4 -----> 3K2SO4 + 3H2O + 3 I2 I2 + 2Na2S2O3 -------> 2NaI + Na2S4O6 So 1 mole of KIO3 produces 3 moles of Iodine. 1 moles of iodine reacts with 2 moles of thiosulfate. So 6 moles of sodium thiosulfate react with 1 mole of potassium iodate KIO3.