NO!!! It is a neutralisation reaction. Reason it produces water (pH =7)
KOH + HBr = KBr + H2O
KBr (Potassium bromide) is a (chemical) salt.
Remember the the empirical acid equations.
Acid + Alkali = Salt + water
Acid + Base = Salt + water
Acid + metal = Salt + hydrogen
Acid + carbonate = Salt + Water + Carbon dioxide.
NB
Acid formulas are always writen as 'HA'. Where 'A' is the anion.
Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation.
NNB Notice the positions of the 'H' in these formulas.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF β KF + H2O.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O
The balanced equation for potassium hydroxide (KOH) and hydrochloric acid (HCl) is: KOH + HCl -> KCl + H2O
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF β KF + H2O.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O
The balanced equation for potassium hydroxide (KOH) and hydrochloric acid (HCl) is: KOH + HCl -> KCl + H2O
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) to form potassium chloride (KCl) and water (H2O) is: HCl + KOH β KCl + H2O
The balanced equation is 2K + 2H2O -> 2KOH + H2, balancing the atoms on both sides of the equation.
The balanced equation for the reaction of sulfur trioxide with potassium hydroxide is: SO3 + 2KOH -> K2SO4 + H2O.
The balanced chemical equation for potassium hydroxide (KOH) reacting with carbon dioxide (CO2) to form potassium carbonate (K2CO3) and water (H2O) is: 2 KOH + CO2 β K2CO3 + H2O
The balanced chemical equation for acetic acid (HC2H3O2) in vinegar reacting with potassium hydroxide (KOH) is: HC2H3O2 + KOH -> KC2H3O2 + H2O This balanced equation shows that one molecule of acetic acid reacts with one molecule of potassium hydroxide to form one molecule of potassium acetate and one molecule of water.
From the balanced chemical equation, we see that 1 mole of KOH produces 1 mole of H2O. Therefore, 0.400 moles of KOH will produce 0.400 moles of H2O. To find the mass of H2O produced, we need to multiply the number of moles by the molar mass of H2O (18.015 g/mol), giving us 0.400 moles * 18.015 g/mol = 7.21 g of H2O produced.
CH3COOH(aq) + KOH(aq) -> CH3COOK(aq) + H2O(l)