The balanced equation for the reaction between calcium hydroxide (Ca(OH)₂) and sulfuric acid (H₂SO₄) is: Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O.
The symbol equation to make copper sulfate is Cu + H2SO4 + 4H2O2 -> CuSO4 + 2H2O + 2H2O2.
When sodium reacts with sulfuric acid, it will produce sodium sulfate and hydrogen gas. The balanced chemical equation for this reaction is 2Na + H2SO4 -> Na2SO4 + H2.
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
The reaction between sodium and sulfuric acid forms sodium sulfate and hydrogen gas. The balanced chemical equation is: 2Na + H2SO4 -> Na2SO4 + H2
koh + h2so4-khso4 +h2o
The balanced equation for the reaction between calcium hydroxide (Ca(OH)₂) and sulfuric acid (H₂SO₄) is: Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O.
It is NaCO3+H2SO4 ---> NASO4+H2O+CO2
The symbol equation to make copper sulfate is Cu + H2SO4 + 4H2O2 -> CuSO4 + 2H2O + 2H2O2.
When sodium reacts with sulfuric acid, it will produce sodium sulfate and hydrogen gas. The balanced chemical equation for this reaction is 2Na + H2SO4 -> Na2SO4 + H2.
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
The reaction between sodium and sulfuric acid forms sodium sulfate and hydrogen gas. The balanced chemical equation is: 2Na + H2SO4 -> Na2SO4 + H2
The complete net ionic equation for Na2SO4 + Ca(NO3)2 is: 2Na+ + SO4^2- + Ca^2+ + 2NO3- → CaSO4(s) + 2Na+ + 2NO3-
To find the number of molecules in 450 grams of NaSO4, we first need to calculate the number of moles using the molar mass of NaSO4 (142.04 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in the calculated moles.
The reaction between sodium zincate (Na2Zn(OH)4) and hydrogen sulfide gas produces zinc sulfide (ZnS) and water. The balanced chemical equation for the reaction is: Na2Zn(OH)4 + H2S -> ZnS + 2NaOH + H2O
Naso4
An equation is balanced if each atom on one side of the arrow has the exact same amount on the other side. You can balance the equation by adding coefficents in front of the element, but make sure there are the same amount. For example: if you have 3 atoms of Al on the left of the arrow, and 6 atoms of Al on the right side, all you have to do is add the number 2 as a coefficient in front of the first Al to make 6 atoms of Aluminum on each side.