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How would you make 1 liter of a 1 molar solution of CaCl2?

Anonymous

∙ 13y ago

Updated: 5/28/2024

Dissolve 111 g anhydrous CaCl2 in 1 L distilled water.

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More answers

To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).

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Q: How would you make 1 liter of a 1 molar solution of CaCl2?

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Continue Learning about Chemistry

How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?

To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).

What 1 molar aqueous solution has the highest number density of ions 1 Glucose 2 CaCl2 3 NaNO3 4 KCl?

CaCl2 would have the highest number density of ions since it dissociates into 3 ions: one Ca2+ ion and two Cl- ions. This results in a total of 3 ions in solution per formula unit of CaCl2.

How do you prepare 0.1n hypona2s2o4?

To prepare a 0.1N solution of hyponatrite (Na2S2O4), you would first need to calculate the molar mass of the compound. Then, you would dissolve the calculated mass of hyponatrite in a sufficient amount of water to make a 1 liter solution, as 0.1N corresponds to 0.1 moles per liter.

How many grams are in 0.74 moles of CaCl2?

To find the number of grams in 0.74 moles of CaCl2, you would first need to determine the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. Then, you would multiply the number of moles (0.74) by the molar mass (110.98 g/mol) to obtain the mass in grams. Therefore, 0.74 moles of CaCl2 is equivalent to 82.21 grams.

How many grams of KCl is needed to make 2 molar solution in 1 liter of water?

To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.

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Related Questions

How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

To prepare a 0.700 M solution of CaCl2 in 2.00 L of solution, you would need 2.00 L * 0.700 mol/L = 1.40 moles of CaCl2. With the molar mass of CaCl2 being 110.98 g/mol, you would need 1.40 moles * 110.98 g/mol ≈ 155.37 grams of CaCl2.

1 Molar solution of Lactose?

A 1 molar solution of lactose would contain 342.30 grams of lactose per liter of solution. This concentration would give you one mole of lactose molecules in one liter of solution.

What is the mass of 0.89 mol of CaCl2?

To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.

How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?

To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).

What 1 molar aqueous solution has the highest number density of ions 1 Glucose 2 CaCl2 3 NaNO3 4 KCl?

CaCl2 would have the highest number density of ions since it dissociates into 3 ions: one Ca2+ ion and two Cl- ions. This results in a total of 3 ions in solution per formula unit of CaCl2.

How do you prepare 0.1n hypona2s2o4?

To prepare a 0.1N solution of hyponatrite (Na2S2O4), you would first need to calculate the molar mass of the compound. Then, you would dissolve the calculated mass of hyponatrite in a sufficient amount of water to make a 1 liter solution, as 0.1N corresponds to 0.1 moles per liter.

How much water should be added to 98 mg of sodium azide to give a 1 molar solution?

To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.

How many grams of KCl is needed to make 2 molar solution in 1 liter of water?

To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.

How many grams are in 0.74 moles of CaCl2?

To find the number of grams in 0.74 moles of CaCl2, you would first need to determine the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. Then, you would multiply the number of moles (0.74) by the molar mass (110.98 g/mol) to obtain the mass in grams. Therefore, 0.74 moles of CaCl2 is equivalent to 82.21 grams.

How many grams of calcium chloride are needed to make a 0.01 M solution?

To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.

How many grams of CaCl2 equal 3.40 moles of CaCl2?

The molar mass of CaCl2 is 110.98 g/mol. To find the mass of 3.40 moles of CaCl2, you would multiply the number of moles by the molar mass: 3.40 moles x 110.98 g/mol = 377.192 g. Therefore, 3.40 moles of CaCl2 is equal to 377.192 grams of CaCl2.

Can you prepare 1 liter of a .5-molar glucose solution?

To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.

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