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Beryllium sulfate is soluble in water.

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8y ago
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6mo ago

You can distinguish between BeSO4 and BaSO4 based on their solubility in water. BeSO4 is soluble in water, while BaSO4 is insoluble. Additionally, you can use a flame test to detect the presence of barium in BaSO4, as barium produces a green flame when heated.

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Q: How would you distinguish between BeSO4 and BaSO4?
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What results from the dissociation of BaSO4?

The dissociation of BaSO4 in water results in the formation of Ba2+ ions and SO42- ions. BaSO4 does not completely dissociate in water, as it is considered insoluble, and only a very small amount of ions will be present in solution.


What is the simplest formula for 0.080 mole Ba and 0.080 mole S and 0.320 mole O?

The simplest formula based on the given moles would be BaSO4 (barium sulfate). This is determined by dividing each mole value by the smallest mole value (0.080 mole), resulting in a ratio of 1 Ba : 1 S : 4 O, which corresponds to BaSO4.


What test that would be able to distinguish between glucose and ribose?

Benedict's test can distinguish between glucose and ribose. Glucose will give a positive result by forming a colored precipitate, while ribose will not react with Benedict's reagent, remaining clear blue.


Solid barium peroxide is added to cold dilute sulfuric acid?

This reaction would produce barium sulfate, water, and oxygen gas. The balanced chemical equation is: BaO2 + H2SO4 → BaSO4 + H2O + O2


Can 24-dinitrophenylhydrazine reagent distinguish between an aldehyde and a ketone?

Yes, 2,4-dinitrophenylhydrazine (2,4-DNPH) can be used to distinguish between aldehydes and ketones. When 2,4-DNPH is added to a carbonyl compound, it forms an orange/red precipitate called a dinitrophenylhydrazone. Aldehydes form this precipitate readily, whereas ketones may take longer to react or may not react at all under certain conditions. This difference in reactivity can be used as a qualitative test to distinguish between the two functional groups.

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BaSO4 + 2H2O --> Ba(OH)2 + H2SO4 There is now one Barium, one Sulfate, two hydroxides, and two oxygens on either side of the arrow. The above reaction would make sense if barium sulfate was soluble in water... but it is not. In fact, it is so insoluble in water that there is no reaction.


What solvent would separate BaSO4 and quinidine?

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