The structure of a tertiary carbocation in Chapter 5 would have three alkyl groups bonded to the positively charged carbon atom. This arrangement provides stability due to the electron-donating inductive effect of the alkyl groups. The positive charge on the carbon atom is offset by the electron density from the adjacent alkyl groups, making this carbocation more stable compared to primary or secondary carbocations.
The conjugate acid of CH3 (methane) would be CH5+, which is an unstable species known as a methyl cation.
CH5, is it existed, would not be an element but a compound as it contains two elements bonded together (carbon and hydrogen). But CH5 cannot exist as carbon cannot bond with more than 4 other atoms.CH4 is the compound known as methane.
Methane can be protonated by superacids to the carbonium ion: H+ + CH4 -> [CH5]+ So methane is a Lewis base but, like helium, it is an exceedingly feeble proton abstractor. and They can lose a proton, but their tendency to lose a proton is so small that the term acid would not normally be applied to them.
The empirical formula for C9H20 is C3H7. This is because we divide the subscripts by their greatest common factor, which in this case is 3.
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
Methanium is not a stable compound; however, its formula would be CH5+.
Yes, CH5 is a molecular formula that represents a hypothetical carbon hydrogen compound. However, CH5 does not correspond to any stable molecule as hydrogen can only form one covalent bond.
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There is no such compound. CH4 is methane (aka natural gas).
CH5 is not a possible molecular formula because hydrogen typically forms one bond, so it cannot form five bonds to carbon in a stable molecule.
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The conjugate acid of CH3 (methane) would be CH5+, which is an unstable species known as a methyl cation.
CH5, is it existed, would not be an element but a compound as it contains two elements bonded together (carbon and hydrogen). But CH5 cannot exist as carbon cannot bond with more than 4 other atoms.CH4 is the compound known as methane.
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The empirical formula for C8H10 is CH5. This is found by dividing the subscripts in the molecular formula by their greatest common factor.