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A complete answer would require specification of a temperature, but at 20C, mercury is reported to have a density of 13.5939 grams per milliliter, so that 1.80 mL would have a mass of 1.80 X 13.5939 or 245 grams, to the justified number of significant digits. The gram Atomic Mass, which is the mass of Avogadro's number of mercury atoms, is 200.6; and Avogadro's Number is about 6.022 X 1023. Therefore the number of atoms in the volume specified is (245/200.6)(6.022) X 1023 or 7.345 X 1021 atoms.

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9y ago
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5mo ago

To determine the number of atoms in 1.80 mL of Mercury, you need to know the density of mercury and its molar mass. Once you have this information, you can calculate the number of moles of mercury in 1.80 mL and then convert this to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).

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Q: How of atoms are in 1.80 mL of mercury?
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