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50mL minus the volume of 0.3 moles pure HCl is how much water is necessary. Be sure to add acid to water never water to acid.

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12y ago
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1mo ago

To prepare a 6M hydrochloric acid solution, you would need to dilute the concentrated hydrochloric acid. The volume of concentrated acid required would depend on its concentration. However, assuming the concentrated acid is 12M, you would need to mix 25 cm3 of the concentrated acid with 25 cm3 of water to prepare 50 cm3 of 6M HCl solution using the formula M1V1 = M2V2.

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Q: How much water must be mixed with concentrated hydrochloric acid to prapare 50cm3 of 6m hcl solution?
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Related questions

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