10 inches of Mercury (in. Hg) is approximately equal to 3.42 psia (pounds per square inch absolute). This conversion is commonly used in barometric pressure measurements.
The molar mass of mercury (Hg) is 200.59 g/mol. In 200.6g, there would be 1 mole of Hg, which is equal to 6.022 x 10^23 atoms. In 400.1g, there would be 2 moles of Hg, which is equal to 1.2044 x 10^24 atoms.
To convert 60 mm Hg to Pascal (Pa), you can use the conversion factor: 1 mm Hg = 133.322 Pa. Therefore, 60 mm Hg is equal to 60 x 133.322 = 7999.32 Pa.
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mole). 9.03 x 10^24 atoms / 6.022 x 10^23 atoms/mole ≈ 15 moles. Therefore, 9.03 x 10^24 atoms of mercury is equal to approximately 15 moles.
To convert inches of mercury (in Hg) to kilopascals (kPa), you can use the conversion factor of 1 in Hg = 3.38639 kPa. Therefore, 23.8 in Hg is equal to approximately 80.6 kPa.
There are 1.92 x 10^23 atoms in 0.3173 mol of Hg. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of Hg.
0 mmHg is equivalent to 0 psia because both represent a pressure of zero relative to absolute vacuum. However, 760 mmHg is equal to 14.7 psia, not 0 psig. 760 mmHg is equivalent to atmospheric pressure, which is the reference point for psig.
2 hg is equal to 200 grams.
The molar mass of mercury (Hg) is 200.59 g/mol. In 200.6g, there would be 1 mole of Hg, which is equal to 6.022 x 10^23 atoms. In 400.1g, there would be 2 moles of Hg, which is equal to 1.2044 x 10^24 atoms.
6 x 10^7 or 60,000,000 g
1 hg = 10 dag so 45 hg = 10*45 = 450 dag.1 hg = 10 dag so 45 hg = 10*45 = 450 dag.1 hg = 10 dag so 45 hg = 10*45 = 450 dag.1 hg = 10 dag so 45 hg = 10*45 = 450 dag.
1444 Torr is equal to 1925.06 mm Hg.
what is 99'' of static pressure equal to in hg(mercury)
mm Hg is a non SI unit of pressure !
I suppose by Hg you mean hectograms? 1 hg = 100 grams, and 1 mg = 1/1000 gram. There are therefore 100,000 mg in a hg, or 1 mg = 10-5 hg. So 17.37 mg = 17.37 x 10-5 hg, or 1.737 x 10-4 hg
no
1 kg = 10 hg so 110 kg = 110*10 = 1100 hg. Simple!
At 13,000 feet above sea level, the average barometric pressure is around 559 millibars.