The energy required to evaporate 5 grams of toluene can be calculated using the heat of vaporization of toluene, which is about 38.5 kJ/mol. Knowing the molar mass of toluene is about 92 g/mol, we can first convert the mass to moles, then calculate the energy required. The energy required can be estimated to be around 8 kJ.
To determine the number of moles in 7.51 grams of toluene, we need to divide the given mass by the molar mass of toluene. The molar mass of toluene is approximately 92.14 g/mol. Therefore, 7.51 grams of toluene is equal to 0.0815 moles.
The density of toluene is approximately 0.865 grams per milliliter at room temperature (20°C).
To make a 100 ppm (parts per million) toluene solution, you would add 100 grams of toluene to 1,000,000 grams (1,000 liters) of solvent (such as water or another liquid). This ensures that there are 100 parts of toluene for every 1 million parts of the solution.
The molar mass of benzene (C6H6) is about 78 g/mol and toluene (C7H8) is about 92 g/mol. Calculate the number of moles of benzene and toluene in the solution using the given masses. Calculate the total number of moles in the solution (benzene + toluene) and then determine the mole fraction of each component by dividing the number of moles of each component by the total moles.
If you evaporate 10 grams of salt in 50 ml of water, all of the salt will remain once the water has completely evaporated. Evaporation only removes the water, leaving behind the salt.
To determine the number of moles in 7.51 grams of toluene, we need to divide the given mass by the molar mass of toluene. The molar mass of toluene is approximately 92.14 g/mol. Therefore, 7.51 grams of toluene is equal to 0.0815 moles.
The density of toluene is approximately 0.865 grams per milliliter at room temperature (20°C).
If the fluid ounce in US is 29,573 529 562 5 mL and the density of toluene at20 0 is 0,87 g/mL, the mass is 25,73 g.
1 kilogram = 1000 grams. You now have all the information required to work out, for yourself, the answer to this and similar questions. And whether that is chicken or not makes no difference.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
To make a 100 ppm (parts per million) toluene solution, you would add 100 grams of toluene to 1,000,000 grams (1,000 liters) of solvent (such as water or another liquid). This ensures that there are 100 parts of toluene for every 1 million parts of the solution.
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
The change in temperature is 21 degrees Celsius. To calculate the energy required, we use the formula: Energy = mass * specific heat * change in temperature. Plugging in the values, Energy = 1.3g * 0.131 J/g°C * 21°C = 35.247 Joules. Therefore, 35.247 Joules of energy is required to heat 1.3 grams of gold from 25°C to 46°C.
The molar mass of benzene (C6H6) is about 78 g/mol and toluene (C7H8) is about 92 g/mol. Calculate the number of moles of benzene and toluene in the solution using the given masses. Calculate the total number of moles in the solution (benzene + toluene) and then determine the mole fraction of each component by dividing the number of moles of each component by the total moles.
To prepare the phenoxide, dissolve 23.5 grams of Csl-IsOl-I in 875 milliliters of toluene. On a separate dish, dissolve 10 grams of NaOH in 150 milliliters of methyl alcohol. Pour the solution into a flask and mix.
If you evaporate 10 grams of salt in 50 ml of water, all of the salt will remain once the water has completely evaporated. Evaporation only removes the water, leaving behind the salt.