It appears that "65g mg" is unclear and does not make sense. If you provide more context or clarify the question, I would be happy to help answer it.
One kg = 1000 grams. So one gram is 10^-3 kilograms. One milli gram is 10^-3 gram = 10^-6 kg. Kilograms and grams are both the metric units of mass. So the answer is 0.065 KG
The molar mass of FeO is 71.85 g/mol, and the molar mass of Fe is 55.85 g/mol. Using the reaction's stoichiometry, we find that 65.0 g of FeO corresponds to 45.85 g of Fe. Therefore, the percent yield of Fe is (33.0 g / 45.85 g) x 100 = 71.96%.
Object B will displace more water because it has a higher density compared to object A. Displacement of water is determined by the density of the object, not its mass.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
A weight of 64.5 grams also equals 0.0645 kilograms.
18.6%
65000 mg
65 grams of what?
It appears that "65g mg" is unclear and does not make sense. If you provide more context or clarify the question, I would be happy to help answer it.
65g
65 000 mG1 cg ;)
There are four fluorine atoms in one molecule of CF4. To find the number of moles of CF4 in 65g, we would divide the mass by the molar mass of CF4. Then, knowing that there are four fluorine atoms per molecule, we can calculate the total number of fluorine atoms in 65g of CF4.
65g = 4.333 tablespoons Also, 1 TBS = 15ml
there are 1000 mg in a gram, so .65g
Its density is 1 g/cm3
65g