To make 1M HCl from 12M HCl, you can dilute the 12M HCl by adding water. The dilution process involves adding a specific amount of 12M HCl to a larger volume of water to achieve the desired concentration of 1M HCl. Calculate the volume of 12M HCl and water needed using the dilution formula C1V1 = C2V2, where C1 and V1 are the initial concentration and volume of the 12M HCl, and C2 and V2 are the desired concentration and volume of the final 1M HCl solution. Mix the solution thoroughly to ensure proper mixing.
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.
To make a 5mM solution of HCl, you would need to dilute concentrated HCl (usually in the range of 10-12M) with water. The exact dilution volume will depend on the concentration of the concentrated HCl solution you have. It's crucial to wear appropriate personal protective equipment and handle concentrated HCl with care due to its corrosive nature.
Hydrochloric acid (HCl) has a density of approximately 1.2 grams per cubic centimeter, which is equivalent to roughly 10 pounds per gallon.
To make 1M HCl from 12M HCl, you can dilute the 12M HCl by adding water. The dilution process involves adding a specific amount of 12M HCl to a larger volume of water to achieve the desired concentration of 1M HCl. Calculate the volume of 12M HCl and water needed using the dilution formula C1V1 = C2V2, where C1 and V1 are the initial concentration and volume of the 12M HCl, and C2 and V2 are the desired concentration and volume of the final 1M HCl solution. Mix the solution thoroughly to ensure proper mixing.
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
438 grams.
To make 0.6M HCl (hydrochloric acid), you would need to dilute a more concentrated solution of hydrochloric acid with water to achieve the desired molarity. For example, to make 1 liter of 0.6M HCl from concentrated 12M HCl, you would need to mix approximately 50 mL of 12M HCl with 950 mL of water. It is essential to add the acid to water slowly while stirring to prevent splashing and ensure safety.
To make a 5mM solution of HCl, you would need to dilute concentrated HCl (usually in the range of 10-12M) with water. The exact dilution volume will depend on the concentration of the concentrated HCl solution you have. It's crucial to wear appropriate personal protective equipment and handle concentrated HCl with care due to its corrosive nature.
around £12m ;)
Up to $12m
Hydrochloric acid (HCl) has a density of approximately 1.2 grams per cubic centimeter, which is equivalent to roughly 10 pounds per gallon.
The weight of one liter of hydrochloric acid would depend on its concentration. For example, a 1M solution would weigh approximately 1.18 kg, while a more concentrated solution like 12M would weigh around 11.15 kg.
1m = 100cm, therefore 12m = 1200cm. 12m is > 120 cm
Flying fish typically weigh between 2-4 pounds, although some species can weigh up to 5 pounds. Their weight can vary depending on the species and their size.
To make a 1 molar solution of HCl from a 12 molar stock solution, you can dilute 1 part of the 12 molar HCl with 11 parts of water (since 1/12 = 0.083). For example, you could mix 10 mL of 12 molar HCl with 110 mL of water to get 120 mL of 1 molar HCl solution.