To determine the amount of acid needed for a 27,000-gallon pool, you would first need to test the pH level of the pool water. Then, based on the current pH level and the desired pH level, you can calculate the amount of acid required using a pool calculator or consulting with a pool professional. It is important to follow safety guidelines and manufacturer instructions when adding chemicals to your pool.
Assuming that you mean that your pure acid is twice as concentrated as your 50% acid. Pretending your pure acid is at 1 mol/gallon and the 50% acid is 0.5 mol/gallon1 molgallon-1 * x gallons = x mol0.5 molgallon-1 * 4 gallons = 2 mol(x + 2) mol for (x+4) gallons = 0.8(x+2) mol / (x+4) gallons= 0.8 molgallon-1x + 2 = 0.8x + 3.20.2x = 1.2x = 6add 6 gallons of pure acid to the 4 gallons to make 10 gallons of 80% acid solution
It will not be accurate, as mixing 1 gallon of acid with one of water will not make 2 gallons. But approximately 7714 gallons of 100% acid would be needed to make a 30% volume/volume acid solution. Your problem now is that very few liquid acids come as 100%, and most that do are very dangerous around water.
When citric acid is added, or any acid for that matter, the pH of a substance will decrease. This is because since acids have a low pH they will decrease the pH of other substances when added to it.
When an alkali is added to an acid, the pH increases as the acid is neutralized by the base. This reaction forms water and a salt. The pH ultimately depends on the strength of the acid and the alkali.
The conversion rate from pounds to gallons depends on the specific gravity of the substance. For phosphoric acid, which has a specific gravity higher than water (around 1.88), one pound would be approximately 0.22 gallons.
You need 17 gallons for a 15% volume/volume mixture.
x = amount of acid to add. y = final volume. 5 gal + x = y original amount of acid + acid added = final amount of acid (5 X .2) + x = O.5y Subtract the second equation from the first one. 5 - 1 + x - x = y - 0.5y 4 = 0.5y 8 = y Therefore the final volume is 8 gallons. 5 gal + x = 8 x = 3 gal. the amount of pure acid to add. Check the answer 5 X .2 = 1 gal of acid in original solution. 3 gallons added = 4 gallons total acid in solution. 4 gallons total acid in final solution of 8 gallons total solution = 50% acid.
Let x be the gallons of the 80% acid solution needed. The amount of acid in the 80% solution is 0.8x, and the amount in the 16% solution is 0.16*60=9.6. We want a total of (x+60) gallons of solution with 60% acid, so we have the equation 0.8x + 9.6 = 0.6(x+60). Solving for x gives x = 24 gallons.
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
Assuming that you mean that your pure acid is twice as concentrated as your 50% acid. Pretending your pure acid is at 1 mol/gallon and the 50% acid is 0.5 mol/gallon1 molgallon-1 * x gallons = x mol0.5 molgallon-1 * 4 gallons = 2 mol(x + 2) mol for (x+4) gallons = 0.8(x+2) mol / (x+4) gallons= 0.8 molgallon-1x + 2 = 0.8x + 3.20.2x = 1.2x = 6add 6 gallons of pure acid to the 4 gallons to make 10 gallons of 80% acid solution
It will not be accurate, as mixing 1 gallon of acid with one of water will not make 2 gallons. But approximately 7714 gallons of 100% acid would be needed to make a 30% volume/volume acid solution. Your problem now is that very few liquid acids come as 100%, and most that do are very dangerous around water.
The answer will depend on the acid, which do not have the same density.
about 5000 gallons to 200 gallons they are all different sizes
Sulfuric acid is added to sugar to make carbon
hcl
is soluble in water and will fizz when hydrochloric acid is added
When citric acid is added, or any acid for that matter, the pH of a substance will decrease. This is because since acids have a low pH they will decrease the pH of other substances when added to it.