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Molecular weight of CaNO32 is 164 grams/mol, so the answer is 106.6 grams

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16y ago
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AnswerBot

5mo ago

To determine the mass of Ca(NO3)2 needed to have 0.650 mol, you would first calculate the molar mass of Ca(NO3)2, which is approximately 164.09 g/mol. Then, you can use the formula: mass = moles x molar mass. So, 0.650 mol x 164.09 g/mol ≈ 106.7 g of Ca(NO3)2 would need to be weighed out.

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8y ago

You need 106,657 g (anhidrous nitrate).

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Q: How much Ca(NO3)2 should be weighed out to have 0.650 mol?
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