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How many moles of sodium hydroxide are required to neutralize water from pH 2.0 to ph 3?
Wiki User
∙ 12y ago
First things first: anything that is pH 2.0 is not water, it's a moderately powerful acid. Lemon juice, for instance, is pH 2.0. Orange Juice is pH 3.
Next, we don't know how much of this acid you need to make less acidic. Certainly a glass of lemon juice is going to require less NaOH to bring its pH up than will a barrel of it.
Wiki User
∙ 12y ago
To determine the number of moles of sodium hydroxide required, we first calculate the change in hydrogen ion concentration from pH 2 to pH 3 (pH change of 1 corresponds to a 10-fold change in H+ concentration). Then, we use the balanced chemical equation between sodium hydroxide and water to determine the amount of moles needed for neutralization.
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How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
What volume of 6 m sodium hydroxide is required to neutralize 50.0 ml of 2.5 m phosphoric acid?
To determine the volume of 6 M sodium hydroxide needed to neutralize 50.0 mL of 2.5 M phosphoric acid, you must first calculate the number of moles of phosphoric acid present (mol = M x L). You then use the balanced chemical equation to determine the mole ratio between phosphoric acid and sodium hydroxide (in this case, it's 2 moles of NaOH for each 1 mole of H3PO4). Finally, you calculate the volume of 6 M sodium hydroxide needed using the molarity and moles obtained.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
How may milliliters of 0.200 moles Sodium Hydroxide are required to completely neutralize 5.00 milliliters of 0.100 moles Phosphoric acid?
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
What volume of 6 m sodium hydroxide is required to neutralize 50.0 ml of 2.5 m phosphoric acid?
To determine the volume of 6 M sodium hydroxide needed to neutralize 50.0 mL of 2.5 M phosphoric acid, you must first calculate the number of moles of phosphoric acid present (mol = M x L). You then use the balanced chemical equation to determine the mole ratio between phosphoric acid and sodium hydroxide (in this case, it's 2 moles of NaOH for each 1 mole of H3PO4). Finally, you calculate the volume of 6 M sodium hydroxide needed using the molarity and moles obtained.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
What would require the largest volume of 0.100M sodium hydroxide solution for neutralization?
The largest volume of 0.100M sodium hydroxide solution would be needed to neutralize a strong acid with a low molarity. This is because a lower molarity acid would require more moles of sodium hydroxide to neutralize it, resulting in a higher volume of the solution being needed.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
How may milliliters of 0.200 moles Sodium Hydroxide are required to completely neutralize 5.00 milliliters of 0.100 moles Phosphoric acid?
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
Determine the number of moles of sodium hydroxide produced when 2 moles of sodium and 3 mol of water react to form soduim hydroxide and hydrogen gas?
The balanced equation for the reaction is: 2Na + 2H2O → 2NaOH + H2 From the equation, 2 moles of sodium will produce 2 moles of sodium hydroxide. So, in this case, 2 moles of sodium will produce 2 moles of sodium hydroxide.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many moles of sodium sulphate can be formed from two moles of sodium hydroxide?
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
How can you calculate the concentration of a phosphoric acid solution from the titration with sodium hydroxide?
You can calculate the concentration of a phosphoric acid solution by determining the volume of sodium hydroxide needed to neutralize it in a titration. The molarity of the sodium hydroxide solution and the balanced chemical equation for the reaction will allow you to find the moles of phosphoric acid present, hence the concentration.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
You would have 1.5 moles of sodium hydroxide. This is calculated by dividing the mass of sodium hydroxide by its molar mass: 60 grams / 40 grams/mole = 1.5 moles.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
