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For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. KCl= 74.6 grams

50.0 grams KCl / (74.6 grams) = .670 moles KCl

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βˆ™ 15y ago
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βˆ™ 5mo ago

To determine the number of moles of potassium iodide in 50 grams, you need to know the molar mass of potassium iodide, which is approximately 166 grams/mol. By dividing the given mass by the molar mass, you can calculate the number of moles. So, 50 grams of potassium iodide would be approximately 0.301 moles.

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βˆ™ 8y ago

50 g potassium iodide is equivalent to 0,3 moles.

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βˆ™ 14y ago

0.388 moles

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Q: How many moles of potassium iodide are there in 50 grams?
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How many moles of iodine are needed to react with 5 moles of potassium to create potassium iodide?

Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.


How many grams are in 0.02 moles of beryllium iodide moles of beryllium iodide?

To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.


How many moles of potassium iodide are needed to make 750 ml of a 1.8 M solution?

To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.


How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?

To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.


How many grams of potasium carbonate are in 1.5 moles of this substance?

The molar mass of potassium carbonate (K2CO3) is approximately 138.21 g/mol. Therefore, 1.5 moles of potassium carbonate would be equal to 207.32 grams (1.5 moles * 138.21 g/mol).

Related questions

How many grams of potassium iodide will produce 750 grams of silver iodide when there is an excess of silver nitrate?

530,3 g potassium iodide are needed.


How many moles of iodine are needed to react with 5 moles of potassium to create potassium iodide?

Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.


How many grams are in 0.02 moles of beryllium iodide?

0.02 moles of beryllium diiodide = 5,256 grams


How many grams are in 0.02 moles of beryllium iodide moles of beryllium iodide?

To find the number of grams in 0.02 moles of beryllium iodide (BeI2), you would first calculate the molar mass of BeI2, which is 262.83 g/mol. Then, you would multiply the molar mass by the number of moles: 0.02 moles * 262.83 g/mol = 5.26 grams of beryllium iodide.


How many grams are in 34.7 moles of potassium?

34,7 moles of potassium 1 356,7 g.


How many moles of potassium iodide are needed to make 750 ml of a 1.8 M solution?

To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.


How many moles are in 45 grams of potassium oxide?

45/94.2 is 0.4777 moles


How many grams of potassium sulfate are there in 25.3 moles?

25,3 moles of potassium sulfate hva a mass of 4,4409 kg.


How many moles are in 156 grams of potassium?

3.99 or 4


How many grams are in 2.2 moles of potassium sulfide?

242.594 g


How many grams of potassium permanganate are in 2.20 moles?

To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.


He formula for potassium dichromate is KËÃCrËÃOΓ‹Γˆ How many grams of oxygen will be in 2 moles of potassium dichromate?

In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.