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How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
Wiki User
∙ 11y ago
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
Wiki User
∙ 11y ago
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How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
Symbol equation for potassium hydroxide and nitric acid?
The reaction between potassium hydroxide and nitric acid produces potassium nitrate and water. The symbol equation for this reaction is: 2KOH + HNO3 → KNO3 + H2O.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How is potassium hydroxide different from dilute nitric acid?
Potassium hydroxide is a strong base, while dilute nitric acid is a strong acid. Potassium hydroxide is alkaline, whereas dilute nitric acid is acidic. They have different chemical properties and uses in various processes.
What is the word equation for potassium hydroxide nitric acid?
Potassium hydroxide reacts with nitric acid to form potassium nitrate and water. The word equation for this reaction is: potassium hydroxide + nitric acid -> potassium nitrate + water.
What mass of potassium hydroxide is required to neutralize 95.00ml of 0.025m nitric acid?
The answer is o,13 g KOH.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200M nitric acid solution?
262 - 266
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200 M nitric acid solution?
262 - 266
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
Symbol equation for potassium hydroxide and nitric acid?
The reaction between potassium hydroxide and nitric acid produces potassium nitrate and water. The symbol equation for this reaction is: 2KOH + HNO3 → KNO3 + H2O.
What is the compound that reacts with potassium to form potassium hydroxide?
Potassium Hydroxide(KOH) is a base (it is "basic"). An acid will neutralize a base. Acetic acid can be used to neutralize KOH. Baking soda is a base, so it will not work to neutralize KOH.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How is potassium hydroxide different from dilute nitric acid?
Potassium hydroxide is a strong base, while dilute nitric acid is a strong acid. Potassium hydroxide is alkaline, whereas dilute nitric acid is acidic. They have different chemical properties and uses in various processes.
What is the word equation for potassium hydroxide nitric acid?
Potassium hydroxide reacts with nitric acid to form potassium nitrate and water. The word equation for this reaction is: potassium hydroxide + nitric acid -> potassium nitrate + water.
What volume of 0.0550 M calcium hydroxide is required to neutralize 35.00 mL of 0.0550 M nitric acid?
To determine the volume of calcium hydroxide needed to neutralize the nitric acid, you can use the equation n1v1=n2v2, where n is the number of moles and v is the volume. As the concentration and volume are given for both the acid and base, the volumes of both solutions needed to neutralize each other will be equal. Therefore, the volume of 0.0550 M calcium hydroxide required will also be 35.00 mL.
How can neutralized potassium hydroxide?
To neutralize potassium hydroxide, add an acid such as hydrochloric acid (HCl) in a 1:1 stoichiometric ratio until the pH is close to 7. The reaction will produce water and potassium chloride salt. Use a pH meter to monitor and ensure complete neutralization.
