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How many moles are there in 37 grams of calcium hydroxide?
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?
To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.
How many moles are in 3.6 g H2 O?
To find the number of moles in 3.6 g of H2O, we first need to calculate the molar mass of water (H2O). The molar mass of water is approximately 18.0153 g/mol. Then, we use the formula: moles = mass / molar mass. Therefore, 3.6 g / 18.0153 g/mol ≈ 0.1997 moles of H2O.
At Which temperature does catalase produce the most oxygen?
Catalase produces the most oxygen at its optimal temperature of around 37°C, which is body temperature in humans. At this temperature, the enzyme's activity is maximized, leading to the highest rate of hydrogen peroxide decomposition and oxygen production.
How many electrons protons and neutrons does rubidium have?
Rubidium has 37 electrons, 37 protons, and approximately 48 neutrons.
How many moles are there in 37 grams of calcium hydroxide?
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
What is the Guinness world record for the number of moles on a person's body?
The Guinness World Record for the most moles on a person's body is held by a man named Satish Kumar who had 37 moles covering his body as of 2010.
What is the volume of 0.75 moles of a gas at 37 oC if the pressure is 5.0 ATM?
The volume is 3,81 L.
How many moles are in 5.546 X 1037 formula units of zinc phosphate?
To calculate the number of moles, you first need to find the molar mass of zinc phosphate (Zn3(PO4)2), which is approximately 386.11 g/mol. Then, use the formula: moles = number of formula units / Avogadro's number. Plugging in the values, you get moles = 5.546 X 10^37 formula units / 6.022 X 10^23 mol^-1, which equals approximately 9.22 X 10^13 moles.
What is the pressure of 64.0 g of oxygen gas in a 1.50L container at -37C?
To find the pressure of the oxygen gas, we can use the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature in Kelvin. First, convert -37°C to Kelvin by adding 273.15 (235.15 K). Then calculate the number of moles of oxygen using the given mass (64.0 g) and the molar mass of oxygen (32 g/mol). Finally, substitute the values into the ideal gas law equation to find the pressure.
How many moles aluminum exist in 100.0 grams of aluminum?
The formular you need is M = n/m (molar mass = amount of substance/mass), or n = m/MAluminium has a molar mass of 26.982 g/mol. The given mass is 3 grams. Therefore:n(Al) = 3g / (26.982g/mol) = 0.11mol
What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?
To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.
If the oxygen partial pressure in your mix is 1.3 ata at a depth of 37 msw (122 fsw) what is the fraction of oxygen in the mix?
0.28
How many 100 in 3700?
37
37 kg is equivalent to how many kgs?
37
How many millions are there in 37 864 753?
37
How many is 37 in one ruler?
It is exactly 37.
