The formula mass of NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 60/58.5 = 1.03mol
So there is 1.03 moles of NaCl in a 60 gram pure sample.
To find the moles of salt, we first need to determine the mass of salt in the mixture. Since the mixture is 48% salt, the mass of salt is 0.48 * 74 grams = 35.52 grams. Next, we calculate the moles of salt using the molar mass of salt (NaCl), which is approximately 58.5 g/mol. Therefore, there are 35.52 grams / 58.5 g/mol β 0.61 moles of salt in the mixture.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
To calculate the number of moles in 1 teaspoon of salt, you first need to know the molar mass of salt (NaCl). Next, determine the mass of salt in 1 teaspoon (typically around 5 grams). Finally, divide the mass of salt by the molar mass to get the number of moles present in 1 teaspoon.
The chemical name for salt is sodium chloride, and its formula is NaCl.
There is one atom of sodium (Na) in the formula for table salt (NaCl).
roughly a mole is a unit of measurement used in chemistry to express amounts of a chemical substance, defined as an amount of a substance that contains as many elementary entities as there are atoms in the atomic weight of the substance in grams.Sodium has an atomic weight of 22.99Chlorine has and atomic weight of 35.45NaCl has a molecular weight of 58.44Therefore a mole of NaCl would weigh 58.44 grams117 grams is therefore roughly equal to 2 moles of table salt.
To find the moles of salt, we first need to determine the mass of salt in the mixture. Since the mixture is 48% salt, the mass of salt is 0.48 * 74 grams = 35.52 grams. Next, we calculate the moles of salt using the molar mass of salt (NaCl), which is approximately 58.5 g/mol. Therefore, there are 35.52 grams / 58.5 g/mol β 0.61 moles of salt in the mixture.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
To make a two mole salt solution in two liters of water, you'll need 4 moles of salt (2 moles/L * 2 L = 4 moles). The molar mass of salt (NaCl) is approximately 58.44 g/mol, so 4 moles would be 233.76 grams (4 moles * 58.44 g/mol = 233.76 g).
Two moles of sodium chloride is equivalent to 116,88 (rounded) g.The molar mass of NaCl 58.5 grams per mole. 117 grams of salt is equivalent to two moles. Dissolve this much of salt in exactly 1L of distilled water in a volumetric flask to prepare 2M NaCl.
To calculate the number of NaCl formula units in 0.12 g of crystal salt, you need to convert the mass to moles using the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Divide the mass of the crystal salt by the molar mass of NaCl to find the moles of NaCl, then use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
To calculate the mass of NaCl needed for a 3.00M solution in 1.00 liter: Calculate the molar mass of NaCl (58.44 g/mol). Use the formula Molarity (M) = moles of solute/liters of solution. Convert molarity to moles (3.00 mol/L x 1.00 L = 3.00 mol). Convert moles to grams (3.00 mol x 58.44 g/mol = 175.32 grams). You would need 175.32 grams of NaCl to make 1.00 liter of a 3.00M NaCl solution.
NaCl is the formula unit of sodium chloride (halite, rock salt, table salt, plain salt, common salt, edible salt etc.). NaCl has 2 atoms in the formula unit.
To calculate the number of moles in 1 teaspoon of salt, you first need to know the molar mass of salt (NaCl). Next, determine the mass of salt in 1 teaspoon (typically around 5 grams). Finally, divide the mass of salt by the molar mass to get the number of moles present in 1 teaspoon.
Since salt (NaCl) dissociates into one sodium ion (Na+) and one chloride ion (Cl-) when dissolved in water, you have one mole of sodium ions for every mole of NaCl. Therefore, you would have 0.0512 moles of sodium ions (3.00g / 58.44g/mol = 0.0512 mol) dissolved in water.
The equivalent weight of a salt is the molecular weight of the salt divided by the number of ions produced when the salt dissolves in water. It is used to calculate the amount of salt needed in a reaction based on the amount of ions present.
The answer to the question is 120 grams of water :)