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How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
Wiki User
∙ 13y ago
I assume zinc limits in this reaction. Balanced equation.
Zn + 2HCl -> ZnCl2 + H2
184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn)
= 2.81 moles zinc chloride produced
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Wiki User
∙ 12y ago
The balanced chemical equation for the reaction of zinc with hydrochloric acid is: Zn + 2HCl → ZnCl2 + H2. Therefore, for every mole of zinc that reacts, one mole of hydrogen gas is produced. Since three moles of zinc are reacting, three moles of hydrogen gas will be produced.
Wiki User
∙ 13y ago20 mol HCl gives 10 mol H2 weighting 10 (mol) * 2 (g/mol) = 20 g Hydrogen, but ONLY when there is (just) enough zinc (also 10 mol Zn = 10*65.4 = 654 g !!) to react!
Zn + 2 HCl --> H2 + ZnCl2
Wiki User
∙ 13y agoCorrection: The correct balanced equation is Zn + 2HCL = ZnCl2 + H2
Wiki User
∙ 12y agomol of H2= 3mol Zn * 1mol H2/ 1mol Zn = 3mol H2
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∙ 13y ago1 mole of H2 gas is produced for every mole of magnesium and ever 2 moles of hydrochloric acid.
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∙ 12y ago3 mol Zn x 1H2 / 1 MOL zN = 3 MOL H2
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∙ 12y agododo birds
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∙ 12y agothree
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∙ 12y agosix
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