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150/132 equals 1.136moles

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12y ago
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5mo ago

To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.

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Q: How many moles of ammonium sulfate are in 150g sample?
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Calculate the number of moles contained in 150g of calcium phosphate?

To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.


How many milligrams equal 150g?

There are 150,000 milligrams in 150 grams. To convert grams to milligrams, you need to multiply the gram value by 1,000. So, 150g * 1,000 = 150,000mg.


How many pounds in 150g?

It is equal to 0.3307 pounds approximately. Kilogram is the metric unit and pound is the imperial unit for mass. 1 Kilogram is 2.204 pounds. So we multiply kg by 2.204 to get the equivalent pounds.


What is the maximum amount of P4 that can be produced from 1.0kg of phosphorite if the phorphorite sample is 75 Ca3PO42 by mass?

The molar mass of Ca3(PO4)2 is 310.18 g/mol. From the given data, there is 75% of Ca3(PO4)2 in the sample, so the mass of Ca3(PO4)2 in 1.0 kg of phosphorite is 0.75 kg. This corresponds to approximately 2.41 moles of Ca3(PO4)2 which will produce the same number of moles of P4. This yields about 124.3g of P4 can be produced from the given sample.


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To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.