To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
There are 150,000 milligrams in 150 grams. To convert grams to milligrams, you need to multiply the gram value by 1,000. So, 150g * 1,000 = 150,000mg.
It is equal to 0.3307 pounds approximately. Kilogram is the metric unit and pound is the imperial unit for mass. 1 Kilogram is 2.204 pounds. So we multiply kg by 2.204 to get the equivalent pounds.
The molar mass of Ca3(PO4)2 is 310.18 g/mol. From the given data, there is 75% of Ca3(PO4)2 in the sample, so the mass of Ca3(PO4)2 in 1.0 kg of phosphorite is 0.75 kg. This corresponds to approximately 2.41 moles of Ca3(PO4)2 which will produce the same number of moles of P4. This yields about 124.3g of P4 can be produced from the given sample.
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
Oh, dude, it's like basic math time! So, if you have 1 kilogram, which is 1000 grams, and you take away 150 grams from that, you're left with 850 grams. Like, it's just subtraction, man. Easy peasy lemon squeezy!
.15kg 150g/1kg = 150g/1000g = 150/1000 = 3/20
I'm going to 15 c
150g
That is 30 teaspoons.
150g
1000ml
150g is 5.3 ounces.
150 grams is 5.29 ounces.
At standard temperature and pressure (STP), the molar volume of a gas is approximately 22.4 L. To find the volume of 150g of ozone (O3) at STP, you would first convert the mass of ozone to moles, then use the molar volume to find the volume.
150g = 5.29oz