The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, 1.8 moles of H2 will produce 1.2 moles of NH3.
First, calculate the number of moles of H2 using its molar mass of 2 g/mol. Then, use the balanced chemical equation for the reaction between H2 and NH3 to determine the mole ratio. Finally, convert the moles of H2 to moles of NH3 using the mole ratio and then calculate the number of molecules of NH3 produced.
To find the number of NH3 molecules produced, we would first need to determine how many moles of H2 are in 3.07104 g. Then, we would use the stoichiometry of the balanced chemical equation to find the number of NH3 molecules produced from that number of moles of H2.
From the balanced chemical equation, we can see that 4 moles of NH3 produce 4 moles of H2O. Therefore, 4.5 moles of NH3 will produce 4.5 moles of H2O in this reaction. It is not necessary to consider the number of moles of O2 in this calculation.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
0,044 moles of NH3 can be produced.
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, 1.8 moles of H2 will produce 1.2 moles of NH3.
0,3 moles of nitrogen reacted.
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.
First, calculate the number of moles of H2 using its molar mass of 2 g/mol. Then, use the balanced chemical equation for the reaction between H2 and NH3 to determine the mole ratio. Finally, convert the moles of H2 to moles of NH3 using the mole ratio and then calculate the number of molecules of NH3 produced.
The answer is 1,57.10e27 molecules.
8 mol
To find the number of NH3 molecules produced, we would first need to determine how many moles of H2 are in 3.07104 g. Then, we would use the stoichiometry of the balanced chemical equation to find the number of NH3 molecules produced from that number of moles of H2.