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3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
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How many moles of O2 must react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide?
The balanced chemical equation for the reaction is: 7 Cl2 + 4 O2 -> 2 Cl2O7 From the equation, it is clear that 4 moles of O2 are needed to produce 69.1 moles of Cl2O7. Therefore, you would need 4 moles of O2 to react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide.
How many moles no must react to form 4.67 moles no2?
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
How many moles of O2 must react with 5 moles of Al?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 53.6 moles of water vapor?
Since water is formed by the reaction between hydrogen and carbon dioxide, the moles of water formed is equal to the moles of hydrogen used. Therefore, 53.6 moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 53.6 moles of water vapor.
How many grams of chlorine are required to completely react with 0.65 g of H2 to produce HCl?
1 mole of H2 reacts with 1 mole of Cl2 to produce 2 moles of HCl. The molar mass of Cl2 is 70.9 g/mol. Since 0.65 g of H2 is used, we must calculate the molar amount of chlorine needed, which is 70.9 g/mol x 0.65 g / 2 g. This gives us approximately 23 grams of chlorine required.
How many moles of oxygen must react with 4.50 mol Al?
The answer is 3,375 moles oxygen.
How many moles of O2 must react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide?
The balanced chemical equation for the reaction is: 7 Cl2 + 4 O2 -> 2 Cl2O7 From the equation, it is clear that 4 moles of O2 are needed to produce 69.1 moles of Cl2O7. Therefore, you would need 4 moles of O2 to react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide.
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?
Four moles of potassium chlorate are needed.
How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?
We need 3 moles of potassium perchlorate.
How many moles no must react to form 4.67 moles no2?
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
How many moles of potassium chlorate (KClo3) must be used to produce 6 moles of oxygen?
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
How many moles of sulfur must be burned to give 0.567 moles of so2?
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
How many moles of O2 must react with 5 moles of Al?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
