To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
To calculate the number of moles in 342g of sucrose, divide the given mass by the molar mass of sucrose. The molar mass of sucrose (C12H22O11) is approximately 342.3 g/mol. Therefore, 342g of sucrose is equal to 1 mole.
There are 3.70 x 10^23 atoms in 0.615 moles of 13C. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
The answer is 3,424 mol sucrose.
To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
The answer is 0,0625 mol.
To calculate the number of moles in 342g of sucrose, divide the given mass by the molar mass of sucrose. The molar mass of sucrose (C12H22O11) is approximately 342.3 g/mol. Therefore, 342g of sucrose is equal to 1 mole.
The formula of sucrose is C12H22O11, so we need to find the molar mass of oxygen in this compound. Oxygen has a molar mass of 16.00 g/mol. 100.0g of sucrose contains (11 mol O / 1 mol C12H22O11) * (16.00 g O / 1 mol O) = 176.0g of oxygen.
There are 3.70 x 10^23 atoms in 0.615 moles of 13C. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
0,2 mol sodium contain 1,204.10e23 atoms.
2.65g(1 mol/6.022*1022atoms)
1.203mol
To find the molality, first convert the mass of sucrose to moles by dividing by its molar mass (342.3 g/mol). Then calculate the moles of water in 676g. Finally, divide the moles of sucrose by the kg of water (0.676kg) to get the molality, which would be approximately 0.127 mol/kg.