To calculate the number of moles of carbon (C) in 90g of CO2, you first need to determine the molar mass of CO2.
Carbon has a molar mass of 12.01 g/mol, and CO2 has a molar mass of 44.01 g/mol (12.01 + 2*16.00). So, 90g of CO2 is equal to 90g / 44.01 g/mol = approximately 2.04 moles of CO2.
Since each CO2 molecule contains 1 carbon atom, there are also 2.04 moles of carbon (C) in 90g of CO2.
To find the number of moles of carbon in 90g of carbon dioxide, you need to consider its molar mass. The molar mass of carbon dioxide is 44.01 g/mol. Calculate the moles of carbon using the molar mass, which will be approximately 2 moles.
There is 0.233 moles of C in 0.233 moles of CO2 since there is one carbon atom in each molecule of CO2.
In CO2, there is 1 carbon atom for every 1 molecule of CO2. Therefore, the number of moles of C in 0.00831 moles of CO2 would be 0.00831 moles.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
In the balanced chemical equation for the formation of CO2 from C and O, the ratio of C to O is 1:2. Therefore, for 0.371 mole of C, you would need 0.742 moles of O to combine with it to form CO2.
To find the number of moles of carbon in 90g of carbon dioxide, you need to consider its molar mass. The molar mass of carbon dioxide is 44.01 g/mol. Calculate the moles of carbon using the molar mass, which will be approximately 2 moles.
There is 0.233 moles of C in 0.233 moles of CO2 since there is one carbon atom in each molecule of CO2.
In CO2, there is 1 carbon atom for every 1 molecule of CO2. Therefore, the number of moles of C in 0.00831 moles of CO2 would be 0.00831 moles.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
This is a chemical calculation. 2.5 moles will C reacting with O2.
In the balanced chemical equation for the formation of CO2 from C and O, the ratio of C to O is 1:2. Therefore, for 0.371 mole of C, you would need 0.742 moles of O to combine with it to form CO2.
In one mole of CO2, there is one mole of carbon (C). So if you have 1 mole of CO2, you have 1 mole of carbon.
First, calculate the number of moles in the sample by dividing the number of O atoms by Avogadro's number (6.022 x 10^23). Then, since each CO2 molecule contains 1 C atom and 2 O atoms, you can determine the number of moles of CO2 by dividing the number of moles of O atoms by 2.
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
To calculate the number of moles in 2400g of CO2, we first need to determine the molar mass of CO2. The molar mass of CO2 is approximately 44.01 g/mol (12.01 g/mol for C + 2 x 16.00 g/mol for O). Then, we can use the formula: moles = mass / molar mass. Therefore, 2400g / 44.01 g/mol ≈ 54.5 moles of CO2.
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2