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The molar mass of Al(CN)3 is 105.0337 g/mol. To determine the moles Al(CN)3 in 229 g Al(CN)3, multiply the given mass by 1 mol/105.0337 g.

229 g Al(CN)3 x 1 mol Al(CN)3/105.0337 g Al(CN)3=2.18 mol Ag(NO)3, rounded to 3 significant figures

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5mo ago

To find the number of moles of Al(CN)3 in 229 g, we first need to calculate the molar mass of Al(CN)3. The molar mass of Al(CN)3 is 105 g/mol. Dividing 229 g by the molar mass gives us approximately 2.18 moles of Al(CN)3 in 229 g of the compound.

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Q: How many moles of Al(CN)3 are in 229 g of the compound?
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How many moles of AlCN3 are in 229 g of the compound?

To find the number of moles of AlCN3 in 229 g of the compound, you first need to determine the molar mass of AlCN3. The molar mass of AlCN3 is 144.99 g/mol. Divide the given mass of 229 g by the molar mass to find the number of moles. Moles = Mass / Molar mass Moles = 229 g / 144.99 g/mol Moles ≈ 1.58 moles


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