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573,28 of g of AgCI is equivalent to 4 moles.

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โˆ™ 8y ago
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โˆ™ 5mo ago

To find the number of moles in 573.28 g of AgCl, you need to divide the given mass by the molar mass of AgCl. The molar mass of AgCl is approximately 143.32 g/mol. So, 573.28 g / 143.32 g/mol = approximately 4 moles of AgCl.

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Q: How many moles is 573.28 of g of AgCI?
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