To determine the grams of solute in a solution, you need to know the molar mass of the solute. Multiply the molarity of the solution by the volume in liters to get the number of moles, then multiply by the molar mass to get the grams. In this case, for 2 moles of solute in 500 cm3 (which is 0.5 L), the mass of the solute would be 2 moles/L * 0.5 L * molar mass of solute in g/mol.
Since 1 mole of O2 reacts with 2 moles of hydrogen to produce 2 moles of water, 250 moles of O2 will produce 500 moles of water. Assuming ideal gas behavior and STP conditions, 1 mole of gas occupies 22.4 L, so 500 moles of water will occupy 11,200 liters.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
There are approximately 500 grams in 17.65 ounces.
There are approximately 192 teaspoons in 500 grams of baking soda.
The molar mass of ammonia is 17,031 g.17,031 g NH3-------------------1 mol500 g NH3-------------------------xx= 500/17,031 = 29,36 moles
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
500 grams of what?
500 milligrams is equal to .5 grams.
To find the weight of 500 moles of CuBr, you first need to determine the molar mass of CuBr which is 159.43 g/mol. Then, you can calculate the weight by multiplying the number of moles by the molar mass: 500 moles * 159.43 g/mol = 79,715 g.
There are approximately 15,432 grains in 500 grams.
500 g = 1.10231 lb
2 cups for 500 grams
To determine the grams of solute in a solution, you need to know the molar mass of the solute. Multiply the molarity of the solution by the volume in liters to get the number of moles, then multiply by the molar mass to get the grams. In this case, for 2 moles of solute in 500 cm3 (which is 0.5 L), the mass of the solute would be 2 moles/L * 0.5 L * molar mass of solute in g/mol.
To find the molarity, you first need to calculate the number of moles of Al2O3. The molar mass of Al2O3 is 101.96 g/mol. Since you have 51 grams, that would be 0.5 moles. Next, convert the volume from mL to liters (500 mL = 0.5 L) and then divide the moles by the volume to get the molarity, which is 1.0 M.
Since 1 mole of O2 reacts with 2 moles of hydrogen to produce 2 moles of water, 250 moles of O2 will produce 500 moles of water. Assuming ideal gas behavior and STP conditions, 1 mole of gas occupies 22.4 L, so 500 moles of water will occupy 11,200 liters.
500 grams of water is half a litre.