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To find the number of moles in 11.5 g of C2H5OH, first calculate the molar mass of C2H5OH. The molar mass is 46.07 g/mol. Next, divide the given mass by the molar mass to get the number of moles. Therefore, 11.5 g of C2H5OH is equivalent to 0.25 moles.
To calculate the moles in 11.5 g of C2H5OH (ethanol), you first need to know the molar mass of C2H5OH. This is obtained by adding the mass of the elements: C = 2x12 = 24; H = 6x1 = 6; O = 16.
Thus, 24 + 6+ 16 = 46 g/mole. Then, 11.5 g x 1 mole/46g = 0.25 moles
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How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
What is the mole fraction of ethanol C2H5OH in an aqueous soloution that is 50.0 ethanol by mass?
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
How many moles are in 27.4 g of water?
There are 1.52 moles of water in 27.4 g.
How many grams are there in 1.36 mol of ethyl alcohol?
To convert moles to grams, you need to use the molar mass of ethyl alcohol. The molar mass of ethyl alcohol (C2H5OH) is approximately 46.07 g/mol. Therefore, 1.36 mol of ethyl alcohol would be 1.36 mol x 46.07 g/mol = 62.59 grams.
How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
How many moles are in 115 g of Li?
115/7=16.42mol
How many moles of carbon are in 1.271 grams of ethanol?
To determine the number of moles of carbon in ethanol (C2H5OH), we first calculate the molar mass of carbon in ethanol: 12 g/mol (from the periodic table). Next, we find the number of moles of carbon in 1.271 grams by dividing the mass by the molar mass: 1.271 g / 12 g/mol ≈ 0.106 moles of carbon.
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
The formula for ethyl alcohol is C2H5OH. The mass of 2 moles of ethyl alcohol would be how many grams?
The molar mass of ethyl alcohol (C2H5OH) is 46.07 g/mol. Therefore, the mass of 2 moles of ethyl alcohol would be 92.14 grams (46.07 g/mol x 2 mol).
What is the boiling point of a solution of 25.0 g of c3h8o3 in 250 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
79c
What is the boiling point of a solution of 235.0 g of c2h6o2 in 450 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
80c
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
88c
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19ºc m and the boiling point of c2h5oh is 78ºc?
80c
What is the boiling point of a solution of 1250 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 119cm and the boiling point of c2h5oh is 78c?
35 c
What is the number of moles in 508 g of ethanol?
To find the number of moles in 508g of ethanol (C2H5OH), first calculate the molar mass of ethanol: 2(12.01) + 6(1.01) + 1(16.00) = 46.08 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 508g / 46.08 g/mol ≈ 11 moles.
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19cm and the boiling point of c2h5oh is 78c?
80 degrees Celsius
