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How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
What is the mole fraction of ethanol C2H5OH in an aqueous soloution that is 50.0 ethanol by mass?
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
How many moles are in 27.4 g of water?
There are 1.52 moles of water in 27.4 g.
How many grams are there in 1.36 mol of ethyl alcohol?
To convert moles to grams, you need to use the molar mass of ethyl alcohol. The molar mass of ethyl alcohol (C2H5OH) is approximately 46.07 g/mol. Therefore, 1.36 mol of ethyl alcohol would be 1.36 mol x 46.07 g/mol = 62.59 grams.
