if you mean 10^22 O atoms, then this is how you do it:
(8.16X10^22)/2=4.08X10^22
so there are 4.08X10^22 molecules, divided by 6.022X10^23(1 mole) is
.06775, so there are that many moles of CO2. If you wanted to know how many moles of overall atoms there were, there's 4.08X10^22 molecules, 1 C in each so 4.08X10^22 C, and 8.16X10^22 O=1.224X10^23, and that's how many atoms, so that divided by 1 mole is (most accurate answer i can get you) .2032547326 moles of atoms
so
.2032547326 moles of atoms
or
.06775 moles of molecules/CO2
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
There are 8 moles of P4O10, and each mole of P4O10 contains 4 moles of phosphorus atoms. Therefore, there are 32 moles of phosphorus atoms in 8 moles of P4O10.
There are 9.12 moles of hydrogen atoms in 4.56 moles of NH2NH2. Each NH2NH2 molecule contains 2 hydrogen atoms.
The element with the most moles of atoms in a 1.0 gram sample would be Mo (Molybdenum) as it has the highest molar mass among the given elements (95.94 g/mol). This means that 1.0 gram of Mo would contain the most moles of atoms compared to Se (Selenium), Na (Sodium), and Br (Bromine).
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
The sample of Al that contains 8.18E+23 atoms has more atoms than a 5.16 mole sample of S. This is because one mole of any substance contains Avogadro's number of atoms or molecules, which is approximately 6.022 x 10^23. Since the Al sample has more atoms than this, it contains the greater number of atoms.
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 Γ 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.
The molar mass of phosphorus is approximately 31 g/mol. To find the number of moles in a 100 g sample, divide the mass by the molar mass: 100 g / 31 g/mol = 3.23 mol. Therefore, there are approximately 3.23 moles of phosphorus atoms in a 100 g sample of phosphorus.
Each water molecule contains two hydrogen atoms. Therefore, the number of water molecules present in the sample can be calculated by dividing the number of hydrogen atoms by 2. In this case, 3.6 moles of hydrogen atoms corresponds to 1.8 moles of water molecules. This is equal to approximately 1.08 x 10^24 water molecules.
To find the number of moles of P in the sample, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). So, 3.78 x 10^24 atoms / 6.022 x 10^23 atoms/mol = approximately 6.29 moles of P in the sample.
Number of moles = mass / molar mass, so the answer is the one with the greatest molar mass. This is plutonium.
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
There are 8 moles of P4O10, and each mole of P4O10 contains 4 moles of phosphorus atoms. Therefore, there are 32 moles of phosphorus atoms in 8 moles of P4O10.
A sample of V containing the same number of atoms as Se will weigh more than 20.5 grams because vanadium (V) has a higher atomic mass than selenium (Se). The atomic mass of an element will affect the weight of a sample containing the same number of atoms.