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The formula mass of sodium sulfide, Na2S, is 2(23.0)+32.1=78.1

Amount of sodium sulfide = 73.5/78.1 = 0.941mol

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10y ago
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6mo ago

To determine the number of moles in 73.5 g of sodium sulfide (Na2S), you first need to calculate the molar mass of Na2S, which is 78.04 g/mol. Then divide the given mass by the molar mass to find the number of moles. Therefore, 73.5 g / 78.04 g/mol = 0.942 moles of sodium sulfide.

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Q: How many moles are there in 73.5 g of sodium sulfide?
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