To determine how many miles of calcium nitrate would react with 4.55 moles of Chromium (III) sulfate to produce chromium (III) nitrate, you would first need to write the balanced chemical equation for the reaction between calcium nitrate and chromium (III) sulfate. Then, use the stoichiometry of the reaction to convert moles of Chromium (III) sulfate to moles of calcium nitrate, and finally, convert moles of calcium nitrate to miles using the molar mass.
To calculate the number of grams-moles (gmole) of chromium(II) hydroxide, you need to know the mass of chromium(II) hydroxide in grams and its molar mass. Once you have these values, you can use the formula: gmole = mass (in grams) / molar mass.
There are 4.17 moles of H2O present in 75.0g of H2O.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
The balanced chemical equation for this reaction is: Cr2O3 + 3H2 -> 2Cr + 3H2O. So, according to the equation, 3 moles of hydrogen are needed to convert 1 mole of chromium oxide. Therefore, to convert 5 moles of chromium oxide, 15 moles of hydrogen would be needed.
1.8x10*24
To determine how many miles of calcium nitrate would react with 4.55 moles of Chromium (III) sulfate to produce chromium (III) nitrate, you would first need to write the balanced chemical equation for the reaction between calcium nitrate and chromium (III) sulfate. Then, use the stoichiometry of the reaction to convert moles of Chromium (III) sulfate to moles of calcium nitrate, and finally, convert moles of calcium nitrate to miles using the molar mass.
To calculate the number of grams-moles (gmole) of chromium(II) hydroxide, you need to know the mass of chromium(II) hydroxide in grams and its molar mass. Once you have these values, you can use the formula: gmole = mass (in grams) / molar mass.
The answer is 8,33 moles.
The answer is 0,615 moles.
There are 4.17 moles of H2O present in 75.0g of H2O.
The answer is 14,93 moles.
If 17,4 is grams the number of moles is 0,084.
5,7 moles (SO4)3-.
9.991 Moles (water) 8.982 Moles (heavy water)
None. Moles live underground.
0.0845 moles of tungsten is equal to 0,50887.10e23.