Each molecule of carbon dioxide (CO2) contains 1 carbon atom. Therefore, in 2.5 x 10^21 molecules of carbon dioxide, there are 2.5 x 10^21 carbon atoms.
To determine the mass of 21 mol of nitrogen (N), you need to know the molar mass of nitrogen, which is approximately 14.01 g/mol. Mass = Number of moles * Molar mass Mass = 21 mol * 14.01 g/mol = 294.21 g Therefore, the mass of 21 mol of nitrogen is approximately 294.21 grams.
There are approximately 5.84 x 10^21 carbon atoms in 9.7 x 10^-3 mol of carbon. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon given.
The concentration of oxygen in air is approximately 21%. This means that out of every 100 molecules in the air, around 21 molecules are oxygen. Oxygen is essential for respiration in many organisms, including humans.
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
To convert 3920 molecules of CO2 to moles of CO2, you need to divide the number of molecules by Avogadro's number, which is approximately 6.022 x 10^23. So, 3920 molecules of CO2 is equivalent to approximately 6.51 x 10^-21 moles of CO2.
To convert molecules to moles, you use Avogadro's number which is 6.022 x 10^23 molecules/mol. Divide the number of molecules (4830) by Avogadro's number to find the moles of CO2. In this case, 4830 molecules CO2 is equal to 8.01 x 10^-21 moles CO2.
The mass of the Earth's atmosphere is 5.25x10^21 grams. If we assume the molar mass of air is approximately 29 grams per mole we get:(5.25x10^21) multiplied by Avogadro's constant (6.02x10^23) and then divided by (29 grams/ mol) = 1.09x10^44 molecules of air in the atmosphere.
There are approximately 1.8 x 10^22 molecules in 0.03 mol of carbon dioxide. This is calculated by multiplying Avogadro's number (6.02 x 10^23) by the number of moles.
Each molecule of carbon dioxide (CO2) contains 1 carbon atom. Therefore, in 2.5 x 10^21 molecules of carbon dioxide, there are 2.5 x 10^21 carbon atoms.
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3 0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21 1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions 3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl The formula to solve this problem appears above.
To find the number of molecules in 0.325 g of aspirin, first calculate the number of moles: 0.325 g / 180.2 g/mol = 0.0018 moles. To find the number of molecules, use Avogadro's number (6.022 x 10^23 molecules/mol): 0.0018 moles x 6.022 x 10^23 molecules/mol = 1.0876 x 10^21 molecules.
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
Air is 21% oxygen so 21% of 200 is 42 oxygen molecules.
First, calculate the molar mass of O2 (molecular weight = 32 g/mol). Then, convert the given number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). The result would be approximately 0.067 moles of O2.