The molar mass of water is 18 g/mol, so 29.2 g is equivalent to 1.62 mol of water. Through electrolysis, each water molecule decomposes into 1 molecule of oxygen and 2 molecules of hydrogen. Therefore, 1.62 mol of water will produce 1.62 mol of oxygen molecules, which is equivalent to 9.73 x 10^23 molecules of oxygen.
To find the number of molecules in 54.3 g of water (H2O), you first need to convert the mass of water to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 54.3 g / 18.015 g/mol = 3.013 moles, then, 3.013 moles * 6.022 x 10^23 molecules/mol = 1.816 x 10^24 molecules of H2O in 54.3 g of water.
There are approximately 3.01 x 10^23 water molecules in a block of ice containing 0.500 mol of water (H2O) because 1 mol of water contains 6.022 x 10^23 molecules.
[10.0(g) / 18.0(g/mol H2O)] * 6.02.10+23(molecules/mol) = 3.34.10+23 molecules in 10 g of H2O(never mind the physical state: solid, liquid, vapor; it's all 10.0 grams of it)
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
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Exactly the same number of mols. 1 mol of oxigen atoms produces 1 mol of water molecules.
To calculate the number of water molecules in 1.802 grams, first find the molar mass of water (H2O = 18.015 g/mol). Then, divide the given mass by the molar mass to get the number of moles (1.802 g / 18.015 g/mol = 0.1 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of water molecules (0.1 mol * 6.022 x 10^23 molecules/mol = 6.022 x 10^22 molecules).
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
The molar mass of water is 18 g/mol, so 29.2 g is equivalent to 1.62 mol of water. Through electrolysis, each water molecule decomposes into 1 molecule of oxygen and 2 molecules of hydrogen. Therefore, 1.62 mol of water will produce 1.62 mol of oxygen molecules, which is equivalent to 9.73 x 10^23 molecules of oxygen.
The reactants of water H (2) + O (2) exist as diatomic molecules only. Therefore, 1 mol of Hydrogen + 1 mol of Oxygen will give 2H(2)O (or 2 mols of Water). Water always exists as a diatomic molecule as well, and this is why it will always have 2 molecules as the most basic possible ratio.
The answer is 12,046.1023 molecules.
To find the number of molecules in 54.3 g of water (H2O), you first need to convert the mass of water to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 54.3 g / 18.015 g/mol = 3.013 moles, then, 3.013 moles * 6.022 x 10^23 molecules/mol = 1.816 x 10^24 molecules of H2O in 54.3 g of water.
There are approximately 3.01 x 10^23 water molecules in a block of ice containing 0.500 mol of water (H2O) because 1 mol of water contains 6.022 x 10^23 molecules.
To find this out you simply times 17 by avogadros number 17mol H2O X 6.022x10^23 molecules of anything/mol of anything mols cancel and you are left in molecules of H2O the answer is 1.024x10^25 molecules H2O
[10.0(g) / 18.0(g/mol H2O)] * 6.02.10+23(molecules/mol) = 3.34.10+23 molecules in 10 g of H2O(never mind the physical state: solid, liquid, vapor; it's all 10.0 grams of it)
To find the number of molecules in 95.2 g of water, first calculate the number of moles using the molar mass of water (18.015 g/mol). Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, (95.2 , \text{g} \times \frac{1 , \text{mol}}{18.015 , \text{g}} \times 6.022 \times 10^{23} , \text{molecules/mol}) gives you the number of molecules.